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12
说明: 是matlab相关的基础学习,在我们学校小学期的时候用到了(Matlab based learning in our school primary school period when used)
- 2013-03-25 21:39:08下载
- 积分:1
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Segmentation
these operators can be used for segmentation
- 2010-01-11 03:15:30下载
- 积分:1
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prtools_ac
模式识别工具,包含神经网络 SVM,DT等代码(pattern recogniton tools)
- 2011-05-29 14:35:56下载
- 积分:1
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Report_Proj5_jiangchen_10212020018
设计一个程序,用后向Euler 法/梯形法求解电路系统的MNA 方程(该方程由stamp 程
序得到),其中线性方程的求解采用GCR 迭代法。(Design a program that uses the backward Euler method/trapezoid method for solving circuit system MNA equation (the equation obtained by the stamp program), in which the linear equations using GCR iteration.)
- 2021-01-04 21:58:55下载
- 积分:1
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对未来人口数量进行预测的阻滞增长模型
说明: 对未来的人口数量进行一定的预测,采用的是阻滞增长模型(Predict the future population)
- 2020-06-17 16:40:02下载
- 积分:1
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Mechanisms_and_Robots_Analysis_MATLAB
A good book for robotics system development in Matlab.
- 2009-06-04 00:33:49下载
- 积分:1
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fz
说明: Matlab仿真过程中随机取样生成图形的一个例子(Matlab simulation of random sampling to generate a graphic example of)
- 2011-10-14 13:04:26下载
- 积分:1
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《卡尔曼滤波原理及应用-MATLAB仿真》程序
说明: 卡尔曼滤波相关代码,内含线性卡尔曼,扩展卡尔曼,无迹卡尔曼,交互多模型卡尔曼的代码(Kalman filter related code, including linear Kalman, extended Kalman, unscented Kalman, interactive multi model Kalman code)
- 2020-04-11 19:18:54下载
- 积分:1
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bresenham_line3d
采用3D Bresenham算法在两点间划一直线
% This program is ported to MATLAB from:
% B.Pendleton. line3d - 3D Bresenham s (a 3D line drawing algorithm)
% ftp://ftp.isc.org/pub/usenet/comp.sources.unix/volume26/line3d, 1992
%
% Which is referenced by:
% Fischer, J., A. del Rio (2004). A Fast Method for Applying Rigid
% Transformations to Volume Data, WSCG2004 Conference.
% http://wscg.zcu.cz/wscg2004/Papers_2004_Short/M19.pdf (3D Bresenham algorithm used in a straight line between two points This program is ported to MATLAB from: B. Pendleton. Line3d- 3D Bresenham s (a 3D line drawing algorithm) ftp://ftp.isc.org/pub/usenet/comp.sources.unix/volume26/line3d, 1992 Which is referenced by: Fischer, J., A. del Rio (2004). A Fast Method for Applying Rigid Transformations to Volume Data, WSCG2004 Conference. http :// wscg.zcu.cz/wscg2004/Papers_2004_Short/M19.pdf)
- 2020-09-01 20:18:08下载
- 积分:1
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c
说明: 约瑟夫问题的实现:设有n个人围坐在圆桌周围,现从某个位置m(1≤m≤n)上的人开始报数,报数到k的人就站出来。下一个人,即原来的第k+1个位置上的人,又从1开始报数,再报数到k的人站出来。依此重复下去,直到全部的人都站出来为止。试设计一个程序求出出列序列。(Joseph realized the problem: There are n people sitting around the round table, is from a position of m (1 ≤ m ≤ n) reported on the number of people began to be reported to the k number of people to come forward. The next person, that is, the original positions on the first k+1 people, and from the number reported at 1, then the number reported to the k to stand up. So repeat this until all the others can stand up. Try to design a program derived from the column sequence.)
- 2011-03-23 15:36:50下载
- 积分:1