amijo

CDMA DSSS直接序列扩频函数 MATLAB实现(CDMA DSSS Direct Sequence Spread Spectrum MATLAB function to achieve)

matlab的经典案例，小程序，适用于初学matlab的同学(matlab classic cases for student who are learning matlab)

stbc在锐利信道的4发2收情况下的信噪比与误码率(stbc Channel 4 in the sharp hair under 2 receive signal to noise ratio and bit error rate)

数字信号处理LMS算法，处理输入信号与参考信号的误差，显示收敛曲线(LMS algorithm for digital signal processing, processing the input signal and reference signal of the error, shows the convergence curve)

Program that implements echo watermarking. The basic idea is to embed a watermark by adding an echo to the original sample.

说明：  用MATLAB做的地面动目标检测，通过杂波抑制，dcpa等等相位中心天线技术，来检测出地面的动目标。(this code is the result of the code ,in fact ,it is the result of the code ,it is using the radar to detect the moveing targets in the ground ,that is it.)

Now you can apply many of MATLAB’s data analysis functions to this data set.

拉丁超立方抽样，调用方式如下：S=lhs(m,dist,mu,sigma,lowb,upb) m: a scalar,the number of sample points dist: A row with distribution type flags of basic random variables the value of the flag can be 1 (for uniform distribution, 2(for normal distribution), 3(for lognormal) and 4(for extreme type 1). mu: A row vector comprising the mean value of basic random variables. sigma: A row vector with its length equaligng to mu,including the standard deviation of basic random variables. lowb: a row vector with its elements are the lower bound of the sampling interval upb:a row vector with its elements are the upper bounds of the sampling interval dist,mu,sigma,lowb,upb must have the same length. Output argument S: sampling point matrix, of which each row is a sampling point.(code of Latin Hypercube Sampling)

实现基于贝叶斯阈值的小波图像去噪算法，相比较其它的小波去噪算法而言，去噪效果非常好。(Wavelet image denoising based on Bayesian threshold, compared with other wavelet denoising algorithm, the de-noising effect is very good.)

某市有一码头，每次仅容一辆船停泊装卸货，由于经常有船等候进港，部分人提出要扩建码头。经过调查历史资料发现，码头平均每月停船24艘，每艘船的停泊时间为24±20小时，相邻两艘船的到达时间间隔为30±15小时，如果一艘船因有船在港而等候1小时，其消耗成本为1000元。经预算，扩建码头大约需要1350万元，故市长决策如下：如果未来五年内停泊船只因等候的成本消耗总和超过扩建码头花费则扩建码头，否则，不予扩建。因此，希望你能够帮助市长做出决策。此问题已知到达的大概时间和大概停泊时间，对于此问题用概率统计的方法来做比较复杂，可用程序随机产生到达时间和停泊时间来模拟未来五年内船的停泊，多次模拟预测停泊情况，以做出决策(。-Problem in a city with a terminal expansion dock, each only allow a boat moored loading and unloading, as often there are waiting boat into port, some people proposed to expand pier. Terminal stopping 24 per month, per vessel berthing time of 24 ± 20 hours, the arrival of two adjacent vessels interval 30 ± 15 hours, if a ship due to boat in the harbor while waiting for one hour, and its consumption cost of 1,000 yuan. The budget of about 13.5 million yuan expansion dock, so the mayor decision as follows: If a ship is moored next five years, the cost of waiting more than the sum of consumption spending is expanding marina pier extension, otherwise, not expanded.)