登录
首页 » Visual C++ » dft

dft

于 2011-09-27 发布 文件大小:30KB
0 352
下载积分: 1 下载次数: 5

代码说明:

  学习matlab的傅里叶变化小程序,没问题额(Fourier transform of small learning matlab program, the amount is no problem)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • binary-amplitude-shift
    在现代通信原理课程中,在MATLAB中实现二进制幅移键控调制程序。(In modern communication theory course, to implement in MATLAB binary amplitude shift keying modulation program.)
    2011-10-04 10:42:12下载
    积分:1
  • MATLABGUI
    信号处理与分析,是基于gui的信号处理与分析,相关函数的应用。(Random signal analysis and Process)
    2013-12-25 15:27:36下载
    积分:1
  • 20103112_homework2
    Add, remove, subtract, attach polynomials
    2015-01-13 15:33:46下载
    积分:1
  • ConvertWGStoCarser
    WGS 转换到Carser WGS 转换到Carser(ConvertWGStoCarser ConvertWGStoCarser ConvertWGStoCarser)
    2013-03-20 10:18:35下载
    积分:1
  • nihe1nn
    网上下载的一个程序开发的示例程序,很实用(Download an example of a program development process, it is practical)
    2011-10-11 10:50:56下载
    积分:1
  • BinarySearchSample
    The file name it says everything.........
    2010-01-04 17:53:00下载
    积分:1
  • example4_4
    例4:在sinc(t)信号中叠加噪声,分析对应频谱 fs=100 采样频率,必须大于两倍基带信号最高频率 ts=1/fs 采样时间间隔 T=2 时间窗大小 ( x=x+0.1*randn(1,N) x=awgn(x,-10, measured ) figure plot(t,x) title( 时域信号图 ) xlabel( t /s ) y=fft(x,N) figure if mod(N,2)~=0 N=N-1 end f=linspace(0,fs/2,N/2) plot(f,abs(y(1:N/2))*2/N) title( 叠加噪声的sinc(t)信号频谱 ) xlabel( f /Hz ) figure y0=y(1:N/2) P=y0.*conj(y0)/N P=10*log10(P) plot(f,P) title( 功率谱 ) xlabel( f /Hz ) )
    2010-05-25 20:59:03下载
    积分:1
  • geom3d_2012.04.05
    matlab中多种三维图形的自动生成程序源码(matlab automatically generate a variety of three-dimensional graphics program source code)
    2012-10-21 18:10:14下载
    积分:1
  • 2
    说明:   有一个长度为整数L(1<=L<=10000)的马路,可以想象成数轴上长度为L的一个线段,起点是坐标原点,在每个整数坐标点有一棵树,即在0,1,2,...,L共L+1个位置上有L+1棵树。 现在要移走一些树,移走的树的区间用一对数字表示,如 100 200表示移走从100到200之间(包括端点)所有的树。 可能有M(1<=M<=100)个区间,区间之间可能有重叠。现在要求移走所有区间的树之后剩下的树的个数。 输入: 两个整数L(1<=L<=10000)和M(1<=M<=100)。 接下来有M组整数,每组有一对数字。 输出: 可能有多组输入数据,对于每组输入数据,输出一个数,表示移走所有区间的树之后剩下的树的个数。(Has a length of integer L (1 &lt = L &lt = 10000) of the road, one can imagine a number line segment of length L, the starting point is the coordinate origin, each integer coordinate points in a tree, i.e. 0,1 , 2, ..., L total has L+1 L+1 positions on the tree. Now to remove some trees, tree removed by a range of digitally represented, such as 100 200 represents removed (inclusive) between 100 and 200 all the trees. There may be M (1 &lt = M &lt = 100) intervals, there may be overlap between the intervals. Now, after the number of trees require the removal of all remaining sections of the tree. Input: two integer L (1 &lt = L &lt = 10000) and M (1 &lt = M &lt = 100). Then there is an integer M groups, each with a pair of numbers. Output: there may be multiple sets of input data, for each set of input data, the output of a number indicating the number of the removal of all remaining sections of the tree after tree.)
    2015-03-22 23:35:47下载
    积分:1
  • hunhebiancheng
    matlab C++混编程序,用C++处理数据,由matlab显示画图(matlab C++ mixed program, with C++ process the data displayed by the matlab drawing)
    2013-07-22 16:11:19下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载