zbzh070620

封装帧和解析帧，并有CRC校验，完全是自己手写(Feng binding and parsing frame, and a CRC checksum)

实现使用music算法进行频率估计，并绘图(Achieve the use of music algorithm for frequency estimation, and graphics)

一个小的钢琴模拟程序，用vb开发，支持MIDI端口(minipiano)

void swap1(int x, int y) //值传递 void swap2(int *px, int *py) //指针传递 void swap3(int &x, int &y) //引用传递 的使用(void swap1(int x, int y) //值传递 void swap2(int*px, int*py) //指针传递 void swap3(int &x, int &y) //引用传递 的使用)

并联六自由度上位机vb程序，自带正解逆解程序和实时曲线显示( This is the VB program of Parallel six degrees of freedom , with the positive solution and the inverse solution procedure and real-time curve display)

生产者消费者实现进程的共享 CSemaphore(Producers and consumers)

VC语言编写的并口通信例程，可以对初学者有帮助的小程序。(VC language of parallel communication routines, can be helpful for beginners small procedures.)

设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组，每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。  编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n（n<=200），表示每个数组有n个数。接下来的两行分别是X，Y数组的元素。结果输出 程序运行结束时，将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits.  programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)

该例程参考《Visual C++开发修行实录》，为ADO访问Access数据库的例程，其中详细介绍了ADO访问数据库的步骤，以及查询、修改、删除等SQL语言的使用。(Refer to the routine Visual C++ development practice record , as the ado access access routines, which details the steps of ADO to access the , and query, modify, delete SQL language use. )

Artificial Intelligence For Game Developers