prog1

MATLAB的频谱分析的具体程序及注意事项(the frequency spectrum in matlab)

本光盘的程序是《MATLAB7.x与C/C++混合编程》配套的源程序，请对照该书使用(This CD is the procedure " MATLAB7.x with C/C++ mixed programming" complementary source, please use the control book)

HEED的分簇算法的matlab代码，注释详细，对初学WSN协议的同学很大帮助。(HEED clustering algorithm matlab code, detailed notes for the students of great help beginners WSN protocol)

This guide reviews the rules and syntax of the principle commands that comprise C and its object-oriented cousin, C++. The reference consists of 19 chapters that define operators and the standard input/output, string, character, and more.

利用SIMULINK搭建考虑轮胎非线性后的二自由度车辆整车模型，及其相关m文件。(Using SIMULINK to build vehicles, vehicle model considering the tire nonlinear two degrees of freedom, m files.)

1133671672316介绍matlab的应用(1133671672316 introduced the application of matlab)

说明：   有一个长度为整数L(1<=L<=10000)的马路，可以想象成数轴上长度为L的一个线段，起点是坐标原点，在每个整数坐标点有一棵树，即在0,1,2，...，L共L+1个位置上有L+1棵树。 现在要移走一些树，移走的树的区间用一对数字表示，如 100 200表示移走从100到200之间（包括端点）所有的树。 可能有M(1<=M<=100)个区间，区间之间可能有重叠。现在要求移走所有区间的树之后剩下的树的个数。 输入： 两个整数L(1<=L<=10000)和M(1<=M<=100)。 接下来有M组整数，每组有一对数字。 输出： 可能有多组输入数据，对于每组输入数据，输出一个数，表示移走所有区间的树之后剩下的树的个数。(Has a length of integer L (1 &lt = L &lt = 10000) of the road, one can imagine a number line segment of length L, the starting point is the coordinate origin, each integer coordinate points in a tree, i.e. 0,1 , 2, ..., L total has L+1 L+1 positions on the tree. Now to remove some trees, tree removed by a range of digitally represented, such as 100 200 represents removed (inclusive) between 100 and 200 all the trees. There may be M (1 &lt = M &lt = 100) intervals, there may be overlap between the intervals. Now, after the number of trees require the removal of all remaining sections of the tree. Input: two integer L (1 &lt = L &lt = 10000) and M (1 &lt = M &lt = 100). Then there is an integer M groups, each with a pair of numbers. Output: there may be multiple sets of input data, for each set of input data, the output of a number indicating the number of the removal of all remaining sections of the tree after tree.)

说明：  简单的评分系统 实现去掉一个最高分与去掉一个最低分然后取平均值的运算(Simple scoring system to achieve the highest score and remove to remove a minimum score and then taking the average of a computing)

Base64编码说明 Base64编码要求把3个8位字节(3*8=24)转化为4个6位的字节(4*6=24),之后在6位的前面补两个0,形成8位一个字节的形式。 如果剩下的字符不...(Base64-encoded instructions require the Base64 encoding three 8-bit bytes (3* 8 = 24) was converted to 4 6 bytes (4* 6 = 24), then in front of the two s complement 6 0, 8 is formed bits in a byte form. If the rest of the characters do not ...)

光纤通信的书，里面有基于matlab的通信仿真(Optical fiber communication book, which has matlab-based communication simulation)