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CA9260
带Java扩展的ARM926EJ-S内核, 2 x 8KB快取, MMU
2x4k Bytes SRAM, 32kBytes Boot ROM
210MHz, 230MIPs
EBI –可支持SDRAM, NAND Flash (带ECC)和Compact Flash
USB控制器和USB器件口, V2.0全速
Ethernet MAC - 10/100
图像传感器界面 (CMOS传感器界面)
1 SSC可支持I2S和TDM
2 SPI, MCI (SDCard和MMC兼容), TWI
6 USARTs, 支持IrDA, ISO7816 T=0/T=1, RS485(Java extension with ARM926EJ-S core, 2 x 8KB cache, MMU2x4k Bytes SRAM, 32kBytes Boot ROM210MHz, 230MIPsEBI- can support SDRAM, NAND Flash (with ECC) and Compact FlashUSB controller and the USB device port, V2.0 full speed Ethernet MAC- 10/100 Image Sensor Interface (CMOS sensor interface) 1 SSC can support I2S and TDM2 SPI, MCI (SDCard and MMC compatible), TWI6 USARTs, support for IrDA, ISO7816 T = 0/T = 1, RS485)
- 2008-08-12 13:33:00下载
- 积分:1
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switch-to-another-window
VC6.0 MFC基于对话框的编程,如何切换到另一窗口(VC6.0 MFC based dialog ,how to switch to another window)
- 2015-02-14 17:01:03下载
- 积分:1
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THQ
此文件是谭浩强C程序设计(第四版)配套PPT课件。内容比书本精炼,简洁,针对性更强。(This file is Hemopurification C Programming (Fourth Edition) supporting PPT courseware. Refined than the contents of the book, concise and targeted.)
- 2011-08-09 19:13:52下载
- 积分:1
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485546
设置列表控件的显示方式,VC++精选编程源码,很好的参考资料。(Set display mode list control, VC++ programming source code, a good reference.)
- 2013-12-01 14:08:17下载
- 积分:1
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Josephus
说明: 实现编程中最经典的问题:约瑟环问题。通过利用链表形式实现该功能。利用C编写。(Programming to achieve the most classic problems: the issue of Joseph Central. Form through the use of the feature list. Prepared to use C.)
- 2009-08-10 19:43:36下载
- 积分:1
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asmmodel
易语言汇编模块源码 献给新手学习. 支持所有汇编代码(Easy assembly language source module dedicated to novice learning. Support for all assembly code)
- 2010-02-17 07:52:44下载
- 积分:1
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gc
说明: 简单垃圾回收器本人以多次试用效果不错,请大家多提意见
(Simple garbage collector I would like to try the effect of a good many times, please do so everyone)
- 2007-08-07 10:54:52下载
- 积分:1
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medo
设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组,每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。 编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n(n<=200),表示每个数组有n个数。接下来的两行分别是X,Y数组的元素。结果输出 程序运行结束时,将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits. programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)
- 2021-03-22 16:29:16下载
- 积分:1
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Blind
volterra 系统的盲辨识,高阶统计随机输入(Blind Identification of Second Order Volterra SystemsWith
Complex Random Inputs Using Higher Order Cumulants)
- 2016-08-01 09:21:30下载
- 积分:1
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Wavelet-Transform
基于TMS320C5502的小波变换程序,代码简洁,适合作于学习DSP开发的学习参考程序(TMS320C5502-based wavelet transform procedures, the code is simple and suitable for the development of learning to learn DSP reference program)
- 2013-07-13 21:35:12下载
- 积分:1