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AIMI561
This the free version of my Basis of AI Backprop designed to
accompany my not yet published textbook, _The Basis of AI_. This
program contains enough features for students in an ordinary AI or
Neural Networking course. It includes the quickprop and delta-bar-delta
algorithms for faster training and a fast integer version for machines
without floating point hardware.
This particular package includes C source for DOS and UNIX, examples, an
ASCII manual and a number of DOS binaries. The binaries are for systems
with floating point hardware (bp.exe), one for systems without floating
point hardware (bp486sx.exe) and an integer version binary
(ibp486sx.exe) for systems without floating point hardware.
- 2007-11-10 11:59:38下载
- 积分:1
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first_bp
心电信号处理之 处理和扩展,ptt计算血压(ECG signal processing and handling of extensions, ptt calculate blood pressure)
- 2014-09-10 19:51:38下载
- 积分:1
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iso_simplicial
Code that performs cardinality constrained optimization for different filter types
- 2014-09-05 13:23:55下载
- 积分:1
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search_by_policy_last
this application is used to search in data base to get some data with special specificaton
- 2010-05-12 03:36:36下载
- 积分:1
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@rtdxhelp
说明: 一个MATLAB的应用程序,很方便的!使用时需要转换为M文件。(A MATLAB application, very convenient! The use of M need to convert files.)
- 2006-03-16 16:30:41下载
- 积分:1
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egao
一个关机恶搞程序,仅供娱乐,其实很简单就用了system函数(A spoof shutdown procedures, for entertainment purposes only, is actually very simple to use system functions)
- 2013-11-13 07:11:43下载
- 积分:1
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PCA_Nicolas
一个基于PCA_Nicolas的matlab编程,可以实现人脸识别的功能(Based on PCA_Nicolas of matlab programming, face recognition function can be achieved)
- 2010-01-05 09:53:36下载
- 积分:1
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GLCM
说明: 这个程序是用MATLAB编写得一个灰度共生矩阵特征及其一些参数得计算,希望对大家有用。(The MATLAB program is written, a GLCM features and some of the parameters was calculated, and I hope useful.)
- 2011-02-20 11:30:11下载
- 积分:1
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CPN
cpn算法例程,主要用c++实现,分两层实现,等等,自己看吧,(CPN algorithm routines, the main c++ achieved, divided into two levels to achieve, and so on, their own look,)
- 2008-12-16 11:06:32下载
- 积分:1
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beibaowenti
有N件物品和一个容量为V的背包。第i件物品的费用是c,价值是w。求解将哪些物品装入背包可使这些物品的费用总和不超过背包容量,且价值总和最大。(There are N items and a knapsack capacity of V' s. No. i is the cost of items c, the value of w. Solving items into the backpack which will enable the cost of these items does not exceed the sum of the capacity of backpack, and the sum of the maximum value.)
- 2009-05-07 22:10:10下载
- 积分:1