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MST_Kruskal
本资料是关于MST_Kruskal算法的matlab实现程序(MST_Kruskal matlab)
- 2011-08-13 10:47:20下载
- 积分:1
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rscode_AWGN_MQAM
RS编码的simulink 仿真,在ANGW条件下1(RS coding simulink simulation conditions in ANGW 1)
- 2010-10-08 22:08:58下载
- 积分:1
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Cholesky
半正定矩阵cholesky方法将其分解为两个上下三角矩阵相乘的形式。matlab自带的函数只能分解正定矩阵。并且给出例子。(Semi-definite matrix cholesky method be decomposed into two upper and lower triangular matrices form. matlab built-in function can only be positive definite matrix decomposition.)
- 2020-08-10 14:48:32下载
- 积分:1
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DPDGOOD
数字预失真的很好的算法,从原理到算法都给出比较详细的说明,对初学者有很大的帮助。(A good digital pre-distortion algorithm to the algorithm are given from the principle of a more detailed explanation, very helpful for beginners.)
- 2021-03-16 15:19:21下载
- 积分:1
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spatial_ZF_SIC
the code simulates the MIMO-OFDM spatial multiplexing with successive interference cancellation
- 2012-05-22 22:34:02下载
- 积分:1
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MATLABsanjiao
基于 matlab 的三角分解法,推荐(based on Matlab 1.3 decomposition method, recommended!)
- 2007-05-09 20:29:50下载
- 积分:1
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fourierslice
验证傅里叶切片定理,可减少傅里叶变换的计算量(fourier slice)
- 2021-05-06 17:58:37下载
- 积分:1
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RLS
自适应信号处理方面的RLS自适应线性预测算法程序(Adaptive signal processing for adaptive linear prediction algorithm RLS procedure)
- 2008-06-14 10:57:22下载
- 积分:1
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Multi-User-Diversity-vs
In a multiple transmit antenna, single antenna per receiver downlink channel with limited channel state feedback, we consider the following question: given a constraint on the total system-wide feedback load, is it referable to get low-rate/coarse channel feedback from a large number of receivers or high-rate/high-quality feedback from a smaller number of receivers? Acquiring feedback from many receivers allows multi-user diversity to be exploited, while high-rate feedback allows
for very precise selection of beamforming directions. We show that there is a strong preference for obtaining high-quality feedback, and that obtaining near-perfect channel information from as many receivers as possible provides a significantly larger sum rate than collecting a few feedback bits from a large number of users.
- 2013-11-08 12:10:41下载
- 积分:1
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nonlinear
-u"+u^2=x, 0<x<1
u(0)=0, u(1)=0
- 2011-04-20 21:44:04下载
- 积分:1