THUYEN

模糊神经网络的实现，开发于matlab环境中，可自行修改(matlab)

生成了符合泊松分布的随机变量，包涵了matlab源代码和C++源代码 利用C++生成，利用matlab画图(generate the poisson varibles )

Gfor 用于Jacket 的MATLAB加速插件使用说明书(Jacket reference)

应用于地震勘探领域的资料处理，第一代相干算法处理。(Used in seismic exploration in the field of data processing, the first generation of coherent algorithm processing.)

C++ 生成画图数据，main函数开启matlab engine，分配存储空间，绘图(C++ calls matlab engine to plot graphics)

SIMULINK简明教程，希望对初学者有用(simulink tutorial, I hope useful for beginners)

某市有一码头，每次仅容一辆船停泊装卸货，由于经常有船等候进港，部分人提出要扩建码头。经过调查历史资料发现，码头平均每月停船24艘，每艘船的停泊时间为24±20小时，相邻两艘船的到达时间间隔为30±15小时，如果一艘船因有船在港而等候1小时，其消耗成本为1000元。经预算，扩建码头大约需要1350万元，故市长决策如下：如果未来五年内停泊船只因等候的成本消耗总和超过扩建码头花费则扩建码头，否则，不予扩建。因此，希望你能够帮助市长做出决策。此问题已知到达的大概时间和大概停泊时间，对于此问题用概率统计的方法来做比较复杂，可用程序随机产生到达时间和停泊时间来模拟未来五年内船的停泊，多次模拟预测停泊情况，以做出决策(。-Problem in a city with a terminal expansion dock, each only allow a boat moored loading and unloading, as often there are waiting boat into port, some people proposed to expand pier. Terminal stopping 24 per month, per vessel berthing time of 24 ± 20 hours, the arrival of two adjacent vessels interval 30 ± 15 hours, if a ship due to boat in the harbor while waiting for one hour, and its consumption cost of 1,000 yuan. The budget of about 13.5 million yuan expansion dock, so the mayor decision as follows: If a ship is moored next five years, the cost of waiting more than the sum of consumption spending is expanding marina pier extension, otherwise, not expanded.)

自己写的matlab小程序，用于解线性方程。可以参考下(Their own small programs written in matlab for solving equations. Can refer to)

说明：  vc与matlab混合编程的具体实例，通过vc编译器调用matlab编译的.m文件。(vc mixed with Matlab programming specific examples, vc call Matlab Compiler compiled. M documents.)

Matlab中生成MIF格式的文件，满足Quartus中载入数据需要(Matlab generated MIF file formats to meet the data needs to load Quartus)