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stego
Simple steganography code to hide text inside image
The code include embedding and extracting procedure
- 2014-09-03 14:00:28下载
- 积分:1
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Grey-Model(2)
灰色模型GM(1,1)的matlab代码(Gray model)
- 2011-11-09 09:26:12下载
- 积分:1
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Pallecant
方程求根的matlab程序,用的是平行法则,仅供参考(Roots of the equation matlab program, using a parallel rule, for reference only)
- 2011-09-27 10:41:43下载
- 积分:1
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FFT-VCPP-1024-point
FFT VC++ 源码 50HZ 1024点 电压波形MATLAB验证 绝对正确 易修改为32点 64点128点 256点512点1024点等 C文件可直接应用于工程,非常好的C源码.rar(FFT 1024 point 512 point 128 point 64 point 32point)
- 2012-11-24 11:48:55下载
- 积分:1
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MyCTPTradingSystem
ctp交易程序 ctp交易程序 ctp交易程序 ctp交易程序(ctp trading system)
- 2014-10-13 22:19:08下载
- 积分:1
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Xu-White-model
用C++编写的xu-white模型,适合砂泥岩地层岩石物理建模,很实用(Written by C++ xu-white model, suitable for sand-shale formation rock physics modeling, it is practical)
- 2020-12-25 09:59:04下载
- 积分:1
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3zuoye
某市有一码头,每次仅容一辆船停泊装卸货,由于经常有船等候进港,部分人提出要扩建码头。经过调查历史资料发现,码头平均每月停船24艘,每艘船的停泊时间为24±20小时,相邻两艘船的到达时间间隔为30±15小时,如果一艘船因有船在港而等候1小时,其消耗成本为1000元。经预算,扩建码头大约需要1350万元,故市长决策如下:如果未来五年内停泊船只因等候的成本消耗总和超过扩建码头花费则扩建码头,否则,不予扩建。因此,希望你能够帮助市长做出决策。此问题已知到达的大概时间和大概停泊时间,对于此问题用概率统计的方法来做比较复杂,可用程序随机产生到达时间和停泊时间来模拟未来五年内船的停泊,多次模拟预测停泊情况,以做出决策(。-Problem in a city with a terminal expansion dock, each only allow a boat moored loading and unloading, as often there are waiting boat into port, some people proposed to expand pier. Terminal stopping 24 per month, per vessel berthing time of 24 ± 20 hours, the arrival of two adjacent vessels interval 30 ± 15 hours, if a ship due to boat in the harbor while waiting for one hour, and its consumption cost of 1,000 yuan. The budget of about 13.5 million yuan expansion dock, so the mayor decision as follows: If a ship is moored next five years, the cost of waiting more than the sum of consumption spending is expanding marina pier extension, otherwise, not expanded.)
- 2015-04-17 18:59:46下载
- 积分:1
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UPFC-with-series-and-shunt-FACTS-controllers
UPFC with series and shunt FACTS controllers
- 2014-09-21 04:02:44下载
- 积分:1
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LMS
1,、设置变量和参量:
X(n)为输入向量,或称为训练样本
W(n)为权值向量
e(n)为偏差
d(n)为期望输出
y(n)为实际输出
η为学习速率
n为迭代次数
2、初始化,赋给w(0)各一个较小的随机非零值,令n=0
3、对于一组输入样本x(n)和对应的期望输出d,计算
e(n)=d(n)-X^T(n)W(n)
W(n+1)=W(n)+ηX(n)e(n)
4、判断是否满足条件,若满足算法结束,若否n增加1,转入第3步继续执行(, set the variables and parameters:
X (n) is the input vector, otherwise known as the training sample
W (n) for the weight vector
e (n) for the deviation
d (n) is the desired output
y (n) is the actual output
η is the learning rate
n is the number of iterations)
- 2011-12-10 20:22:05下载
- 积分:1
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VC++_Matlab_pdf
说明: Matlab与VC混合编程实例,rar格式(Matlab and VC mixed programming examples, rar format)
- 2005-12-24 11:37:12下载
- 积分:1