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matlab-soc

于 2011-09-09 发布 文件大小:9KB
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下载积分: 1 下载次数: 7

代码说明:

  用于VC与matlab之间的通信,对初学者有好处(Used for communication between VC and matlab, good for beginners)

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    基于MATLAB小波消噪,有很大作用,一代二代三代(MATLAB Wavelet-based de-noising, there is a great role in generation of the second generation of three generations)
    2009-03-19 21:33:05下载
    积分:1
  • matlab
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    2014-02-07 16:17:04下载
    积分:1
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    定义一个描述电视的CTelevision类。类中包含电视品牌(p_brand,使 用指针类型)、当前频道(channel,一共500个频道)和当前音量(volume, 最大30)等数据成员。要求提供缺省以及带参构造函数,以及输出对象信息 方法。(A class definition television CTelevision description. Class contains TV brands (p_brand, so Pointer type), the current channel (channel, a total of 500 channels) and the current volume (volume, Maximum 30) and other data members. Requirements and provides a default constructor with parameters, and output object information Methods.)
    2015-01-29 23:08:50下载
    积分:1
  • ziyouzhendong
    关于自振动仿真的源代码,可以看看,第一传求关注,支持。(Source Courseware)
    2011-05-14 07:54:18下载
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    德国低干扰谱,以及公路C级路面的路面不平度的c++实现。一些相关的资料,便于初学者理解。(German low interference spectrum, as well as C-level road highway pavement roughness achieved. Some relevant information, easy for beginners to understand.)
    2015-04-12 14:35:20下载
    积分:1
  • magicMatrix
    matlab c++ 联合编程简单示例,具体过程可以参照我的blog:http://blog.csdn.net/owldestiny/archive/2009/03/07/3966340.aspx(matlab c++ United programming easy example, the specific process can refer to my blog: http://blog.csdn.net/owldestiny/archive/2009/03/07/3966340.aspx)
    2009-03-08 09:34:43下载
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    一道程序编译顺序的考题,涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的,这道题的重点在“fun((int)fun(a+c,b),a-c)) ”语句。 系统首先要确定最外层 fun()函数的实参,第一个参数的确定需要递归调用fun()函数(不妨称其为内层函数)。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)
    2009-03-15 15:36:23下载
    积分:1
  • guzhangjisuan
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    2014-09-18 15:12:02下载
    积分:1
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    8089s52 based degital voltmeter. usefull project with full report
    2012-09-02 02:52:52下载
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