MATLAB-project--lip-movment

进程操作的类,可以从进程名枚举进程PID,也可以从窗口标题查找,打开进程,读取长整型,写入长整型,读取字节数组,写入字节数组.压缩包内包含有一个破解示例,破解掉一个判断密码是否正确的程序(仅在内存中进行,不破坏原文件)(Process operations class, you can enumerate the process name from the process PID, you can search for the title from the window, open the process, read a long integer, write long integer, byte array to read, write byte array. Tarball sample contains a crack, break out a password to determine whether the correct procedure (only in memory, not a destruction of the original document))

学习模糊控制的经典教材，是一本学习模糊控制的好书，值得大家学习！(Learning fuzzy control is one of the most classic materials, worth learning!)

冈萨雷斯数字图像处理配套第六章matlab例程，代码里面有详细解释，适合初学者同步学习。(Gonzalez digital image processing Chapter 6 of the supporting Matlab routines, the code inside the detailed explanation of the synchronous learning for beginners.)

说明：  最炫民族风的源代码，喜欢的可以下载下来，放在matlab中听一下。另外，这里还有其他音乐代码，需求的可以私信我。(The most unusual national wind source code, like you can download and put matlab liking it. In addition, there are other music code, demand can private letter to me.)

语音小波去噪方法的matlab实现 比较基础 可以看看(Voice Wavelet Denoising matlab can look at the basis for comparison)

小车倒立摆，利用t-s模型与pid调节，比较简单实用(xiao che dao libai li yong pid tiao jie )

mimo+ofdm的功能仿真，实现基本的通信工呢(mimo+ ofdm functional simulation, the basic means of communication to achieve it)

介绍了无线应用中的通信系统的情况以及是如何仿真的。(Introduced a wireless communication system applications, as well as how the simulation.)

1.分别在两个图中画出δ(n)和δ(n-2)，其中-10≤n≤10，画出U（n）其中-10≤n≤10。 2.分别在两个图中画出x1(n)=cos(2π×20×0.01×n)，0≤n≤10和x2(n)=(0.8)n，1≤n≤6。 3.由上一题，计算y(n)=x1(n)+x2(n)，并画图。(1. Draw the figure at two δ (n) and δ (n-2), where-10 ≤ n ≤ 10, draw the U (n) where-10 ≤ n ≤ 10. 2. Respectively in the two Draw the figure x1 (n) = cos (2π × 20 × 0.01 × n), 0 ≤ n ≤ 10 and x2 (n) = (0.8) n, 1 ≤ n ≤ 6. 3. from the previous question, calculate y (n) = x1 (n)+ x2 (n), and drawing.)

fuzzy control of dc drive