Codes

it is neural net work code

biomedical stuffs...

这本书是一个短，重点介绍MATLAB，全面 数学和技术计算软件系统。它将 是有益的到bothbeginning和有经验的用户。它包含简洁 必要的MATLAB命令，以及容易理解的解释 使用MATLAB的编程功能的说明，图形 能力，和桌面界面。它还包括一个介绍 到Simulink，MATLAB的系统仿真的同伴。(This book is a short, focused introduction to MATLAB, a comprehensive software system for mathematics and technical computing. It will be useful to bothbeginning and experienced users. It contains concise explanations of essential MATLAB commands, as well as easily understood instructions for using MATLAB’s programming features, graphical capabilities, and desktop interface. It also includes an introduction to SIMULINK, a companion to MATLAB for system simulation.)

输入参数，可自动提取瑞雷波频散曲线，含使用说明。(The input parameters can automatically extract the Rayleigh Leibo dispersion curve, including the usage description.)

移动节点模型仿真代码和仿真图，适用于wsn移动节点定位算法研究。(Mobile node model simulation code and simulation maps, research wsn mobile node localization algorithm applies.)

基于matlab的图像处理的课程设计 里边包含有程序 很详细的 有做这方面课程设计的 可以看看(Matlab image processing based on the curriculum design inside contains a very detailed procedure to do this course are designed to look)

基于conturlet变换的图像融合,利用conturlet还变来对图形进行处理并融合(Transform based image fusion conturlet transform based image fusion conturlet transform based image fusion conturlet)

mass spring damper example using simulink block diagram

This should be a signal with sin(x) presented

产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度 谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅 度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显 示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)