UKFfiter

离散对称信道的信道容量的计算离散对称信道的信道容量的计算(Discrete symmetric channel is the channel capacity of computing discrete symmetric channel calculation of channel capacity)

说明：  灰色预测matlab程序与散点图的绘制的matlab程序(Grey prediction matlab program and scatter diagram of MATLAB program )

高等光学仿真源程序，有助于了解光纤光学，主要是光在光纤中传播的模式分布(Higher optical simulation program to help understand fiber optics, light propagation in the fiber mode distribution)

matlab power electronics program

电力系统中的有源电力滤波器仿真，其中的谐波检测方法是PQ法，谐波滤除的效果非常好。(Power system simulation of active power filter, where the harmonic detection method is PQ method, harmonic filtering effect is very good.)

function for auv id this file is good for estimation

说明：  low-pass filter 让某一频率以下的信号分量通过，而对该频率以上的信号分量大大抑制的电容、电感与电阻等器件的组合装置。 (low-pass filter )

matlab中tic与toc函数联合进度条使用例子(tic toc function matlab in combination with the use of examples progress bar)

本源程序可用于语音识别的端点检测算法，双门限端点检测算法+基于谱熵端点检测。。。(Double threshold endpoint detection algorithm+ endpoint detection based on spectral entropy)

产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度 谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅 度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显 示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)