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Maze
c++用栈来实现迷宫求解(c语言数据结构)(c++ stack maze solving (c language data structure))
- 2012-10-27 23:08:34下载
- 积分:1
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chain
链表的模板类,提供插入删除,遍历器,查找等功能,只有一个头文件,可以包含到你的工程(template implemention of Chain)
- 2013-12-09 11:04:33下载
- 积分:1
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arrangement
假设要在足够多的会场里安排一批活动,并希望使用尽可能少的会场。设计一个有效的贪心算法进行安排。(这个问题实际上是著名的图着色问题。若将每一个活动作为图的一个顶点,不相容活动间用边相连。使相邻顶点着有不同颜色的最小着色数,相应于要找的最小会场数。)
对于给定的k 个待安排的活动,编程计算使用最少会场的时间表。
(Suppose you want to arrange a number of activities in the hall more than enough, and want to use as little as possible venue. Design an effective greedy algorithm arrangements. (This problem is actually well-known graph coloring problem. If each activity as a vertex map, with the side connected between incompatible activities. Makes coloring adjacent vertices with minimum number of different colors, corresponding to looking The minimum number of venue.)
K to be arranged for a given activity, calculated using a minimum of venue programming schedule.)
- 2014-10-22 11:00:45下载
- 积分:1
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CarClass
数据结构简单的课程设计交通换乘算法,里面有零次换乘与一次换乘(Simple structure, curriculum design data traffic transfer algorithm, which have zero time transfer and a transfer)
- 2011-01-09 10:33:14下载
- 积分:1
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BigNumeberOperator
这是高精度大数运算的源码,对于大于64位的整形数字的四则运算,是万能的啊……(This is the code of big number s operator.)
- 2011-08-09 15:25:09下载
- 积分:1
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heap
实现栈的基本操作,建栈,进栈,出栈,数据结构实现(To achieve the basic operation of the stack, built stack into the stack, the stack data structure)
- 2013-04-03 11:08:37下载
- 积分:1
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xunhuansaiqxf
算法课程设计 分治法解决循环赛日程表 源代码+word报告+答辩PPT(Curriculum design of divide and conquer algorithm to solve a round robin schedule report+ source code+ word reply PPT)
- 2010-05-26 23:51:17下载
- 积分:1
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qiuhe
多项式求和,用链表实现的一元多项式求和程序,比较 靠谱(Polynomial sum, with the linked list implementation of a polynomial summation procedure, more reliable)
- 2011-09-15 09:16:38下载
- 积分:1
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Graph
数据结构中图的遍历Data structure traversal of center(Data structure traversal of center)
- 2013-11-28 10:53:29下载
- 积分:1
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NoGo
计算机博弈大赛不围棋的代码 个人所写,可以用来参考( U8BA1 u7B97 u673A u535A u5F08 u5927 u8D5B u4E0D u56F4 u68CB u7684 u4EE3 u7801 u4E2A u4EBA u6240 u5199 uFF0C u53EF u4EE5 u7528 u6765 u53C2 u8003)
- 2021-04-04 19:39:04下载
- 积分:1