nrsolve

VC++中使用MATLAB的C++数学库和MCC生成的程序，给出了例程，对于高手有借鉴意义，对菜鸟可以起到事半功倍的作用。(VC++ in the use of MATLAB' s C++ Math Library and MCC procedures generated are given routine, you have a reference for the rookie can play the role of a multiplier.)

说明：  使用K-L算法进行特征变换，画出结果图像(Feature transformation, using the KL algorithm to draw the resulting image)

How a Brushed DC Motor works and rotates

C program of binary search

Kmedoid 是类似于Kmean的Clustering method。(Kmedoid is similar to Kmean the Clustering method.)

生成与函数值Y维数相同的时间矩阵,对初学者有一定的帮助！！(cc)

FBMC 在瑞利和AWGN信道下的BER性能仿真(the ber simulation of FBMC in rayleigh and AWGN channel)

我们的目的是将一个分数拆分成若干个分子是1分母是正整数的分数之和的形式。例如2/3可以拆分成1/2+1/6的形式。这里不考虑顺序，比如1/6+1/2和1/2+1/6相同。 输入p, q, a, n, 其中p/q为分数，对这个分数进行拆分，要求拆分的分数个数不能多于n个，所有分母的乘积不能大于a。求有多少种拆分方法? 输入：最多200组数据。在每行中都有四个数分别表示p, q, a, n，之间以空格隔开，并且满足p,q<=800，a<=12000，n<=7，最后以四个0做为输入的结束。 输入示例: 2 3 120 3 2 3 300 3 0 0 0 0 输出示例: 4 7 (Our aim is to split a fraction into a number of elements is a denominator is a positive integer fraction of the sum of form. For example, 2/3 can be split into 1/2+1/6 form. Not considered here, the order, such as 1/6+1/2 and 1/2+1/6 of the same. Input p, q, a, n, where p/q as a fraction of this split scores require no more than the number of split points n-all the product of the denominator can not be larger than a. How many kinds of demand split method? Input: Up to 200 sets of data. In each line has four numbers indicate the p, q, a, n, separated by a space between, and meet the p, q < = 800, a < = 12000, n < = 7, the end, four 0 as the input end. Input Example: 2,312,032,330,030,000 sample output: 47)

用于振动方程求解，其中包含了newmark-B的积分数值求解方法，以及求解过程。(It is used to solve the vibration equation, including the Newmark-B integral numerical method and the solving process)

说明：  能够实现双树复小波包变换，有一段仿真例子可以供大家参考(Realization of dual tree complex wavelet packet transform)