cups

与打印机的通信工具，文件传输工具,也可做渗透打印机。( PJL File Transfer command line interface to PJLlib functionality )

设置多重群组的打印报表，C++Builder精选编程学习源码，很好的参考资料。(Print statements to set multiple group, C++Builder select learning programming source code, a good reference.)

介绍了cups下的打印机驱动开发。对于在开发打印机驱动的朋友，这份文档对你会有很大的帮助。(Introduced the cups printer driver under development. For the printer driver in the development of a friend, this document will be of great help to you.)

说明：  grid++打印条码，特别好用，谁用了就知道了(Grid++ prints barcodes, which are very easy to use. Anyone who uses them knows.)

说明：  条码打印程序，有窗体打印，二进码打印，调用API函数打印等。(Barcode printing procedures form printing, binary code printing, call API function printing.)

C语言实现简单的日志打印，如下所示：前面是时间，后面是要打印的日志内容 2011-09-14 15:09:23 ************************************************** 2011-09-14 15:09:23 start to recordlog 2011-09-14 15:09:23 ************************************************** (C language implementation of a simple log printing file , as follows: the front is the time, followed by a log to print the contents 2011-09-14 15:09:23************************************************** 2011-09-14 15:09:23 start to recordlog 2011-09- 14 15:09:23********************************************)

一个比较简单的c++实例，一个比较简单的c++实例(sample demo)

tribon二次开发 批量打印程序源码 供大家参考(tribon second development batch printing program source code for your reference)

热敏打印机，新唐热敏打印方案。。。。。。。。。(Thermal printer)

题目：打印出杨辉三角形（要求打印出10行题目：输入3个数a,b,c，按大小顺序输出。 题目：输入数组，最大的与第一个元素交换，最小的与最后一个元素交换，输出数组。 题目：有n个整数，使其前面各数顺序向后移m个位置，最后m个数变成最前面的m个数 题目：编写一个函数，输入n为偶数时，调用函数求1/2+1/4+...+1/n,当输入n为奇数时，调用函数1/1+1/3+...+1/n(Topic: Print out the Triangle (10 lines required to print out the Title: Enter the 3 numbers a, b, c, according to the order of output. Title: input array, the largest exchange with the first element, the smallest and the last element of the exchange, output array. Topic: There are n integers, to move back in front of the order m of the number of positions, finally becoming the foremost m m the number of number of topics: write a function, the input n is even, the call function evaluation 1/2+1/4+...+ 1/n, when the input n is odd, call the function 1/1+1/3+...+ 1/n)