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pcm_matlab
pcm编码的MATLAB实现,主要是通过13折线吗,取样量化编码的实现。(pcm encoded MATLAB realize, mainly through the 13 line it, the realization of sampling quantization coding.)
- 2008-07-02 16:12:27下载
- 积分:1
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dxbebylwktbg_mydown0315
我自己编的一个,大家可以看看,我们可以讨论一下(my own addendum to the one, we can see that we can talk about)
- 2007-05-01 21:55:55下载
- 积分:1
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demospp
in this program I have simulated SPP method for iris data.
- 2012-05-27 17:46:17下载
- 积分:1
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uplod4
MIMO OFDM based codings for their resource allocation.
- 2011-02-06 23:01:25下载
- 积分:1
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matlab
频率估计
1)产生一个单频实信号,加上一定信噪比的噪声。
2)对含噪声的信号进行频率估计。估计方法可以查阅相关文献。
3)统计估计出来的频率和真实频率之间的误差。
4)验证该频率估计算法在不同信噪比、不同数据长度下、不同频率时候的性能。
(Frequency estimation 1) produce a single-frequency real signal, plus a certain SNR noise. 2) noisy signal frequency estimates. Estimation method can access relevant literature. 3) out of the statistical estimation and frequency error between the true frequency. 4) Verify that the frequency estimation algorithm under different SNR, different data length, when the frequency of different properties.)
- 2014-04-24 13:11:49下载
- 积分:1
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ga
说明: genetic code with roullet wheal
- 2009-12-31 19:47:52下载
- 积分:1
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CS4VM
this rar file contains matlab code for face recognition using CS4VM. here the implementation was done by using CS4VM method of face recognition.
- 2013-07-16 17:50:16下载
- 积分:1
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LargestLyapunov
这个是用小数据量法计算时间序列最大lyapunov指数的matlab程序(This is a small amount of data calculated time series index of the largest lyapunov Matlab procedures)
- 2021-02-27 00:19:37下载
- 积分:1
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cs_doa
压缩感知实现阵列信号处理 对比MUSIC方法(Compressed sensing array signal processing to achieve contrast MUSIC algorithm
)
- 2013-12-17 23:00:51下载
- 积分:1
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mnyz
一杯沸水冷却,圆柱体模型,底面半径0.05m,高0.1m,周围温度20度,初始水温100度
方程是四维输运方程(常数a^2=k/(c*p),k是热传导系数0.6006焦/(米*秒*度))
初始条件:t=0时水等于100度
边界条件:1.上下壁都是自由冷却,第三类边界条件,周围温度保持在20度(H=k/h,h取1)
2.杯壁绝热,第二类边界条件
图形显示格式,取过圆柱轴的截面温度变化将其做成动画.
(A cup of boiling water for cooling, the cylinder model, the bottom radius of 0.05m, the high-0.1m, an ambient temperature of 20 degrees, the initial water temperature of 100 degrees is four-dimensional transport equation equation (constant a ^ 2 = k/(c* p), k is the thermal conductivity coefficient of 0.6006 J/(m* s* degrees)) initial conditions: t = 0 when the water equivalent to 100 degrees boundary conditions: 1. up and down the wall are free cooling, the third boundary condition, the ambient temperature maintained at 20 degrees (H = k/h, h check one) 2.杯壁insulation, the second boundary condition graphical display format, check-off section of cylindrical shaft temperature change to make animation.)
- 2007-11-06 20:57:53下载
- 积分:1