doa1

家庭监控系统的实现，matlab版的，适合初学的朋友，系统完整(Home monitoring system implementation, matlab version, suitable for beginners friends, system integrity )

APF基于ip-iq的Simulink仿真模型，学习及分析APF很好的资料，验证可用，文件仅用于学习交流，严禁用于商业用途。(APF ip-iq Simulink models based APF study and analysis of good information, verification is available only for study and exchange files, non-commercial use.)

matlab环境下的支持向量机的时间序列预测(Time Series Prediction of Support Vector Machine in Matlab Environment)

PID模糊小车直线控制，用MATLAB编写，运行后绘制小车运动轨迹(PID fuzzy car straight-line control, using MATLAB, and run after drawing the car trajectory)

风力发电系统Matlab仿真，包含定速风机和变速双馈风机(wind power generation system in Matlab, including constant speed generator and DFIG)

所有图论问题的MATLAB程序，包括最短路等等(MATLAB graph theory problem of all procedures, including the short-circuit, etc.)

Direction Detection for image

matlab 中用Bisection方法求解一元多次方程，是一种很好的算法。但收敛速度比较慢，是线性收敛(matlab using Bisection method for solving multiple equations one yuan, is a good algorithm. But convergence is slow, linear convergence)

说明：  收藏了两篇关于Kalman滤波器的经典教程，一篇是英文原版，令一篇是翻译本，对初学者很有帮助。(Kalman Filter )

在一个移动通信系统中，发射信号是一个未调制的音频x(t)=cos(2πft)，其中f=f0+fi。设标称载波为f0=1GHz，并设fi =512Hz。假定移动用户在一个繁忙的高速公路上距离基站l公里处的地方，从开始从每小时60公里的速度开始，其速度（在0.01秒的时间间隔内测量）以1/2的概率随机的增加或减少1/10公里每小时。试仿真移动用户在这2s的时间间隔内所接收到的信号(及其频谱)。接收信号可以表示为： y(t)=a(t)Cos[2π(fo+f1)(t-△t)] 式中 △(t)=d(t)/c 且 a(t)=k/d2(t) 在上面的表达式中d(t)是在t时刻基站与移动用户的距离，c是光速，△(t)是传播延迟，而a(t)是信号在t时刻的衰减，并假设在这2s内a(t)是一个常数。利用复低通等效模型来进行仿真。(In a mobile communication system, the transmitted signal is an unmodulated audio x (t) = cos (2πft), where f = f0+ fi. Let nominal carrier of f0 = 1GHz, and set fi = 512Hz. Assume that mobile users on a busy motorway station l kilometers place, starting the beginning of 60 kilometers per hour, the speed (measured in 0.01 second interval) to increase the probability of a random 1/2 or reducing 1/10 km/h. Simulation test signal which the mobile subscriber in the 2s time intervals of the received (and its spectrum). The received signal can be expressed as: y (t) = a (t) Cos [2π (fo+ f1) (t- △ t)] Where △ (t) = d (t)/c And a (t) = k/d2 (t) In the above expression, d (t) at time t is a base station and a mobile user s distance, c is the speed of light, △ (t) is the propagation delay, and a (t) is the attenuation of the signal at time t, and assuming that 2s within a (t) is a constant. Using complex low-pass equivalent model for emulation.)