-
SVPWM123456
基于svpwm(矢量控制技术)的电机仿真模型,在simulink里面仿真-(Based on svpwm (vector control technology) simulation model of permanent magnet synchronous motor, which in simulink simulation)
- 2010-12-19 21:02:14下载
- 积分:1
-
n
运用matlab这个软件运用递归方法运算出任意一个数的阶乘(The use of this software using a recursive method matlab computing factorial of a number of arbitrary)
- 2013-11-29 14:25:19下载
- 积分:1
-
postme---Copy
The code introduces postcoding technique in ofdm system that results in a much less complex mechanism and provide similar result as are obtained with precoded system. In this technique the coding part is done after the ifft block that is initially the data is converted to frequency domain n then coding is introduced.
- 2011-04-20 20:25:59下载
- 积分:1
-
pulse_response_recognition
基于matlab系统辨识的经典脉冲响应辨识,自己编写,效果不错。(Matlab system identification based on the classic impulse response identification, their preparation, good results.)
- 2010-05-27 15:19:03下载
- 积分:1
-
MATLAB_Simulink_for_DSP_Won_Y_Yang_
在MATLAB中进行DSP控制仿真 (MATLAB_Simulink_for_DSP )
- 2013-08-07 22:17:40下载
- 积分:1
-
PQ
说明: 利用matlab编制的电力系统pq分解法潮流计算(pq flow)
- 2012-05-01 14:59:40下载
- 积分:1
-
bkqshiaz
关联规则挖掘算法的matlab程序,我编写了Apriori算法的LTgqvz 步骤,可以自动生成关联规则,计算支持度、置信度以及 WJFlqaT 检测,很好的小程序。(Association rule mining algorithm matlab program, I wrote LTgqvz step Apriori algorithm can automatically generate association rules, computing support, confidence and WJFlqaT detection, good little program.)
- 2016-01-21 22:27:19下载
- 积分:1
-
ep2.m
Hessenberg solution MATLAB code.
- 2009-11-02 01:42:23下载
- 积分:1
-
daonajuzhen
说明: 形成导纳矩阵的一个小程序,课程设计是做的,希望对你有用(Admittance matrix
)
- 2010-05-24 15:38:23下载
- 积分:1
-
111
function pi = solve2(count,m,cc)
借助布冯投针实验 仿真求pi的值
pi=0
frq=0
randNo = binornd(1,cc,1,m)
pro=zeros(1,count)
for j=1:count
for i = 1:m
if randNo(1,i) == 1
frq = frq + 1
end
pro(i) = frq/i
end
pi = (2*m)/frq
pro(j) = pi
end
pro = pro,num =1:count
plot(num,pro) (function pi = solve2 (count, m, cc) to vote with Buffon needle experiment simulation find the value of pi pi = 0 frq = 0 randNo = binornd (1, cc, 1, m) pro = zeros (1, count) for j = 1: count for i = 1: m if randNo (1, i) == 1 frq = frq+ 1 end pro (i) = frq/i end pi = (2* m )/frq pro (j) = pi end pro = pro, num = 1: count plot (num, pro) )
- 2011-05-24 15:39:41下载
- 积分:1