eigen-eigen-6e7488e20373.tar

matlab processing and realization of the voice, very useful

利用LFSR生成伪随机序列（m序列） 对待隐藏的图像进行加密然后利用线性插值的方法隐藏于载体图像中。 代码很完整 用的是MATLAB7.0(Use LFSR to generate pseudo-random sequence (m sequence) to treat encryption to hide the image and then use linear interpolation method of hidden images in the vector. Complete code is used in MATLAB7.0)

关于matlab fixunknowns函数问题给出我的解答(Give me answers about the issue of the matlab fixunknowns function)

本书全面系统地介绍了DSP芯片的基本原理、开发和应用。首先，介绍了目前广泛使用的DSP 芯片的基本结构和特征，定点和浮点DSP处理中的一些关键问题。然后，对用C 语言和MATLAB 语言进行DSP算法的模拟进行了介绍。(This book a comprehensive and systematic introduction to the basic principles of DSP chips, the development and application. First of all, on current DSP chips are widely used in the basic structure and characteristics of fixed-point and floating-point DSP to deal with some of the key issues. Then, using C language and MATLAB language for DSP algorithm simulation are introduced.)

遗传算法解决作业车间调度问题，这一M文件为遗传算子的交叉操作(Genetic algorithms to solve the job shop scheduling problem, the M-file for the genetic operators crossover operation)

函数可以自动计算标准手份额并显示剩余空间百分比或者使用固定标准手数( х без знака ) 在程序 #include <Lot_Volume.mqh> 中添加函数，同时在需要的位置调用 OrderSend(货币对, 定单类型, Lot_Volume(), 价格, 0, 停止, 赢利) 如果显示为 10 ， 那说明标准手数为10 。如果只是 10 ，那说明为10个标准手。 当然它现在并不完美，等待评论。(Function can automatically calculate and display the remaining share lots of space using a fixed percentage or standard lots ( х без знака ) Add a function in the program#include <Lot_Volume.mqh> while in the desired location to call OrderSend (currency pair, order type, Lot_Volume (), price, 0, stop, profit) If the display is 10 , it shows the standard number is 10 percent hands. If only 10 , it means the 10 standard lots. Of course it s not perfect now, waiting for comment.)

Red object Detection seample

用matlab实现语音的加噪去噪过程，FFT变换(Implementation using matlab voice add process noise denoising, FFT transform)

matlab vs2008混合编程，减少程序移植工作量。(matlab vs2008 mixed programming, reduce the workload of the transplant procedure.)

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)