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getword
获取并替换word表格值,非常实惠好用的小软件,与大家分享。(get word)
- 2012-05-04 09:05:52下载
- 积分:1
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shangrenguohe
商人过河程序,找了好久才找到的程序......(shangrenguohe)
- 2009-12-04 10:57:30下载
- 积分:1
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hun_v61
车牌识别定位程序的部分功能,包括随机梯度算法,相对梯度算法,wolf 方法计算李雅普诺夫指数。( Part of the license plate recognition locator feature, Including stochastic gradient algorithm, the relative gradient algorithm, wolf calculated Lyapunov exponent.)
- 2017-05-12 12:13:15下载
- 积分:1
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sort
说明: 能够实现起泡法,二分法,堆排序,插入排序,选择排序,快速排序六种方法对100个数进行排序的时间空间复杂度进行比较(To achieve foaming method, dichotomy, Heap Sort, Insertion Sort, Selection Sort, Quick Sort six methods on 100 the number of sort of time and space complexity comparison)
- 2008-11-14 20:29:09下载
- 积分:1
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Test
Priorities:
1) Keep It Simple
2) Do not couple to any specific unit test framework.
- use appropriate IdTest.pas units to plug into required framework.
Units are named IdTest*, so they can be easily searched/listed.
eg using UnitExpert (http://www.epocalipse.com/downloads.htm) ctrl-u, "idtest", lists all available test units.
(Priorities:
1) Keep It Simple
2) Do not couple to any specific unit test framework.
- use appropriate IdTest.pas units to plug into required framework.
Units are named IdTest*, so they can be easily searched/listed.
eg using UnitExpert (http://www.epocalipse.com/downloads.htm) ctrl-u, "idtest", lists all available test units.
)
- 2009-09-14 16:21:13下载
- 积分:1
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WORD-VBA
WORD VB 二次编程,实现题库管理与自动出卷功能。(The WORD VB quadratic programming, question bank management, and automatic volume.
)
- 2012-04-09 11:36:00下载
- 积分:1
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sysyem
在 Visual C++中操作Excel,对开发数据库管理系统很有意义(Operation Excel in Visual c + +, is very meaningful to the development of database management system)
- 2017-06-23 10:20:43下载
- 积分:1
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ESRI.ArcGis.Desktop.v9.3.Crack.Only-TBE
arcGIS 9.3破解所需的全部文件。(all the required files for arcgis 9.3)
- 2020-06-25 22:40:02下载
- 积分:1
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music
基于MATLAB的微动目标的信息提取,一人的呼吸心跳为例。(Based on MATLAB s information extraction of micro- moving target, one person s breathing heartbeat as an example.)
- 2021-01-17 10:58:49下载
- 积分:1
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closest_pair
分治法思想,求最邻近点对,考虑将所给的n个点的集合S分成2个子集S1和S2,每个子集中约有n/2个点,然后在每个子集中递归地求其最接近的点对(Divide and conquer ideas, find the nearest point to consider given the set S of n points into two subsets S1 and S2, each subset of about n/2 points, and then recursively find its focus in each sub-the closest point)
- 2013-12-07 16:46:26下载
- 积分:1