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3107002005_5th_spline
说明: 曲线的三次样条插值,在非首尾节点处具有三次光滑性质(Curve cubic spline interpolation, in both nodes with non-smooth nature of the three)
- 2008-10-27 11:07:08下载
- 积分:1
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css
用visual basic编译的布谷鸟算法的源代码,是一种很好地启发式智能算法。(Use visual basic compiler cuckoo algorithm source code, is a good heuristic intelligent algorithm.
)
- 2013-07-19 17:02:51下载
- 积分:1
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MOM
用矩量法(电场结合磁场积分方程)算金属圆柱散射(Using the method of moments (electric field integral equation combined) considered the scattering of metal cylinder)
- 2021-04-04 20:39:04下载
- 积分:1
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2D-TM
2维的FDTD C程序(2-dimensional FDTD C procedures)
- 2008-05-05 07:34:54下载
- 积分:1
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spline
样条插值算法的matlab代码,包括一次样条插值,二次样条插值和三次样条插值,可根据需要选择(Spline interpolation algorithm matlab code, including a spline interpolation, quadratic spline interpolation and cubic spline interpolation, can be selected)
- 2020-12-23 20:49:06下载
- 积分:1
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areaofcircle
一圆形游泳池如图所示,现在需在其周围建一圆形过道,并在其四周围上栅栏。
栅栏价格为35元/米,过道造价为20元/平方米。
过道宽度为3米,
游泳池半径由键盘输入。
要求编程计算并输出过道和栅栏的造价。(A circular pool as shown in figure, now in its built around to a circular corridor, and in its 4 around on the fence.
The fence for 35 yuan/m price, corridor cost for 20 yuan/square metre.
Aisle width is 3 meters,
The radius of the swimming pool by keyboard input.
Demand and output programming calculation of corridor and the cost of the fence.
)
- 2012-04-06 11:29:01下载
- 积分:1
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Simpleequationstoachieve
说明: 利用该方程组求解一般的线性方程组,别且符合数学求解原理(Using the equations of linear equations in general, do not and in accordance with principles of mathematics to solve)
- 2010-04-22 10:38:10下载
- 积分:1
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phase-equivalence
C 语言,模拟流体相平衡过程,得到混合气体平衡态以后的工况参数(C language to simulate fluid phase equilibrium process, to obtain a mixed gas equilibrium after working parameters)
- 2020-09-04 16:48:06下载
- 积分:1
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berth_quay10_8
用于解决港口优化调度的算例,程序可解,且富有详细说明(The optimal scheduling algorithm used to solve the port, the program is solvable, and rich detailed instructions)
- 2020-07-02 20:20:02下载
- 积分:1
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矩阵链乘算法
说明: 距阵链乘问题:
找出矩阵链乘A(35*40) A(40*20) A(20*10)
A(10*15)的最佳相乘次序。
算法来自:计算机算法导引(matrix chain by : identify matrix chain by A (35* 40) A (40* 20) A (20* 10) A (10* 15) concludes the best order. Algorithm from : computer algorithm Seeker)
- 2005-11-17 09:23:42下载
- 积分:1