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OFDMsimu
OFDM仿真,包括详细的解析,对初学者有很好的作用(OFDM simulation, including detailed analysis of the beginners have a good role)
- 2008-03-01 11:26:44下载
- 积分:1
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Optimization_Newton
设r是f(x) = 0的根,选取x0作为r初始近似值,过点(x0,f(x0))做曲线y = f(x)的切线L,L的方程为y = f(x0)+f (x0)(x-x0),求出L与x轴交点的横坐标 x1 = x0-f(x0)/f (x0),称x1为r的一次近似值。过点(x1,f(x1))做曲线y = f(x)的切线,并求该切线与x轴交点的横坐标 x2 = x1-f(x1)/f (x1),称x2为r的二次近似值。重复以上过程,得r的近似值序列,其中x(n+1)=x(n)-f(x(n))/f (x(n)),称为r的n+1次近似值(Let r is f (x) = 0 root, select the initial approximation x0 as the r, over point (x0, f (x0)) to do the curve y = f (x) the tangent L, L the equation y = f ( x0)+ f ' (x0) (x-x0), find the intersection of L and the x-axis of abscissa x1 = x0-f (x0)/f' (x0), x1 is called an approximation r. Through points (x1, f (x1)) to do the curve y = f (x) the tangent, and find the intersection of the tangent with the x-axis of abscissa x2 = x1-f (x1)/f ' (x1), x2 is called r the second approximation. Repeat the process, get an approximation of the sequence r, where x (n+1) = x (n)-f (x (n))/f ' (x (n)), as an approximation of r n+1 times)
- 2011-06-21 21:13:09下载
- 积分:1
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Overlap-and-Save-method
Overlap–save is the traditional name for an efficient way to uate the discrete convolution between a very long signal x[n] and a finite impulse response (FIR) filter h[n].
- 2015-01-20 10:04:16下载
- 积分:1
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matlab-prog-M.Tech-2013
forward and backward search
- 2014-01-09 15:00:58下载
- 积分:1
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doa
matlab信号的DOA估计 music算法 加入循环(bpsk music cyclic doa)
- 2016-07-03 18:41:46下载
- 积分:1
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szfxsy1
实验一:三次样条插值(P56,例6)
一、实验目的:
1) 掌握三次样条插值的运用
2) 了解拉格朗日插值在高次上的误差
二、实验环境:Matlab6.5
三、实验内容:
1) 给定函数f(x)=1/(1+x2),-5<=x<=5,节点xk=-5+k,(k=0,1,2…10),用三次样条插值求S10(x),S10’(-5)=f’(-5),S10’(5)=f’(5)。
2)作原函数f(x),拉格朗日插值函数Ln(x),三次样条差值函数Sn(x)。画出三个函数的图像,比较它们的区别。
(Experiment I: cubic spline interpolation (P56, cases of 6) First, the experiment was: 1) cubic spline interpolation to master the use of 2) understanding of Lagrange interpolation in high-error second, experimental environment: Matlab6 .5 c, experimental elements: 1) a given function f (x) = 1/(1+ x2),-5 <= x <= 5, node xk =- 5+ k, (k = 0,1,2 ... 10), using cubic spline interpolation for S10 (x), S10 (-5) = f (-5), S10 (5) = f (5). 2) for the original function f (x), the Lagrange interpolation function Ln (x), cubic spline difference function Sn (x). Draw the three functions of images, compare the difference between them.)
- 2009-01-18 23:06:15下载
- 积分:1
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lyap_small_data_sets
计算最大Lyapunov指数
使用wolf方法计算
申明:本程序并非本人原创(Calculating the largest Lyapunov index calculated using the wolf has stated: This procedure is not my original)
- 2008-03-03 09:47:20下载
- 积分:1
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TIME-FREQUENCY
Matlab时频分析技术及其应用教材后面的源代码(Frequency analysis technology and its application materials behind when the source code Matlab)
- 2013-12-07 18:11:23下载
- 积分:1
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nengliangguangli
微电网能量管理系统,能量优化,环境的预测(Micro-grid energy management system, energy optimization, environmental prediction)
- 2013-07-02 17:28:40下载
- 积分:1
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Nbinfit-and--kstest
一组随机数据进行负二项分布拟合及拟合优度检验(Nbinfit and kstest)
- 2021-02-17 16:29:46下载
- 积分:1