登录
首页 » matlab » CDMA2000reverse_link_channel_simulation

CDMA2000reverse_link_channel_simulation

于 2007-05-22 发布 文件大小:83KB
0 255
下载积分: 1 下载次数: 150

代码说明:

  对于CDMA2000 1X反向信道仿真,其中包括CRC,卷积,交织,扩频和调制的整个过程,模型和M文件。请查看文件夹中的README。(for CDMA2000 1X reverse channel simulation, including CRC, convolution, interleaving, Spread-spectrum modulation, and the whole process model and the M-file. Please see the folder README.)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • pmsm
    PMSM的simulink模型,MATLAB版本6.5(PMSM the simulink model, MATLAB Version 6.5)
    2008-04-26 08:02:54下载
    积分:1
  • LEsprit
    二维doa估计esprit算法程序,可以较快的对目标doa进行二维角度估计(2D esprit algorithm)
    2015-11-30 15:36:24下载
    积分:1
  • miusiu
    数值分析的EULER法,小波包分析提取振动信号中的特征频率,isodata 迭代自组织的数据分析。( EULER numerical analysis method, Wavelet packet analysis to extract vibration signal characteristic frequency, Isodata iterative self-organizing data analysis.)
    2016-11-06 17:05:35下载
    积分:1
  • mndhyy
    说明:  模拟退火应用的和序,含有gcp,tsp,isp,mcp(Application of simulated annealing and the sequence containing gcp, tsp, isp, mcp)
    2008-09-17 16:31:41下载
    积分:1
  • BPF
    Matlab GUI for bandpass filters
    2010-09-24 22:27:48下载
    积分:1
  • em
    说明:  MATLAB实现的EM算法,用于高斯混合模型的均值、方差、权重估计(EM algorithm based on MATLAB)
    2010-11-28 10:04:13下载
    积分:1
  • dc_line1
    Power flow or load-flow studies are important for planning future expansion of power systems as well as in determining the best operation of existing systems.
    2011-07-13 23:39:25下载
    积分:1
  • ofdm2
    这是一个仿真移动通信信道幅频响应的matlab仿真程序。(This is a simulation of mobile communications channel amplitude frequency response of Matlab simulation program.)
    2007-06-05 00:54:44下载
    积分:1
  • LMS
    经典自适应算法 用LMS算法求最佳权值(Adaptive algorithm with the LMS algorithm for the best weights)
    2012-08-04 17:22:35下载
    积分:1
  • vigenere
    vigenere密码在起初的破译中是靠穷举法,找出与阅读习惯最适合的明文,但是也可以先缩小穷举范围,再查找(vigenere initial crack passwords by brute-force method is to identify the most suitable and clear reading habits, but can also be reduced exhaustive range, and then find)
    2011-10-26 09:53:10下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载