matlab-for-beginner

matlab 计算框架结构模态，频域法计算(matlab calculate frame mode, frequency-domain method to calculate)

bartle自功率谱密度分析，对于直接法的功率谱估计，当数据长度N太大时，谱曲线起伏加剧，若N太小，谱的分辨率又不好，因此需要改进。(Bartle since the power spectral density analysis, for the direct method of power spectrum estimation, when the data length N is too large, the spectrum curve of the ups and downs, if N is too small, the resolution of the spectrum and is not good, so need to improve.)

说明：  protocol implementation for viewing TELEMECHANIC DATA

用matlab 作卡尔曼滤波实验。讲解的步骤清楚，简单易懂(ka er man lv bo)

The system is fully preemptible when this function is called. The kernel does no processing, but it passes all parameters directly to the function supplied by you. （当这个函数被调用的时候系统完全可能被抢占，内核没有处理，直接传递参数到你提供的函数。这个我觉得说的很别扭，估计是直接传递参数到OEMIoControl ）(The system is fully preemptible when this function is called The the kernel does no processing, but it passes are all the parameters directly to the function are supplied by you (When this function is called when the system is entirely possible to seize the kernel did not deal directly pass parameters to the function you provide. I think that is very awkward, and is estimated to pass parameters directly to OEMIoControl))

SAMP 开源都市 非常完美 值得下载 (SAMP perfect city worth downloading open source)

利用Matlab工具在VC dotNet中实现聚点拟合以及直径测算的程序(Matlab tool in achieving VC dotNet accumulation diameter calculation and fitting procedures)

本程序是运用SVM来实现人脸识别算法，能直接运行且能进行二次开发(This procedure is to use SVM to implement face recognition algorithm that can run directly and can perform a secondary development)

多网格求解泊松方程，给出并解释了一个如何使用多网格求解的过程(I give a short explanation of how to use multigrid to solve the Poisson equation in cylindrical coordinates for a solid conducting pipe. I also explain how to use a non-uniform grid to optimize the problem. )

clear 从内存中清除变量和函数 exit 关闭MATLAB load 从磁盘中调入数据变量 pack 合并工作内存中的碎块 quit 退出MATLAB save 把内存变量存入磁盘 who 列出工作内存中的变量名 whos 列出工作内存中的变量细节 workspace 工作内存浏览器 (There is one outlier in the data of , but is not of data .For and the line of Q2 is in the middle of the box, so there are not asymmetries for both and .)