登录
首页 » C++ » RCPCED

RCPCED

于 2007-05-09 发布 文件大小:13KB
0 305
下载积分: 1 下载次数: 47

代码说明:

  仿真程序主体部分由c语言完成,改变运行的设定的参数,在相同的信道编码速率下,通过改变误码率,用Matlab软件进行画图,得出在相同编码速率不同误码率下的纠错后误码的比率,接着改变编码速率,重新可以划出另外的两条曲线;(simulation program from the main part of the completion c language, change the operation of the set parameters, the same channel coding rate, by changing the error rate using Matlab software for drawing, reached the same rate of different coding error rate after correction of the error rate, and then change the coding rate, can be re-drawn the other two curves;)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • AddedChannelequalizationAWGNnoiseeffects
    have further added a very simple Linear Equalizer to the code, where I assume that the channel is perfectly known. Note that for equalization to work here, the prefix length must be equal to or greater than the length of the channel.
    2010-05-23 22:02:41下载
    积分:1
  • lgktsf-matlab
    龙格库塔算法,微分方程组求解,用matlab语言编写。(Runge-Kutta algorithm, the differential equations solved using matlab language.)
    2012-05-21 19:12:45下载
    积分:1
  • QSDASS
    Please read THIS DOCUMENTE
    2013-05-05 10:34:57下载
    积分:1
  • 3.7
    主要用途是对抗多径衰落。由于多径衰落的存在,使得同一个帧由于路径不同,到达用户端的时延有先有后。在相关的频域上的会造成子载波之间的相互干扰,影响 性能。另外,由于有了循环前缀,使得IFFT FFT操作把原来的线性卷积变成循环卷积,大大简化了相应的信号处理复杂度
    2012-08-24 15:18:38下载
    积分:1
  • GPC
    给定传递函数的分子和分母,以及预测时域,预测步长,自动仿真GPC算法。(Given the transfer function, simulate GPC algorithm.)
    2015-03-10 20:41:12下载
    积分:1
  • DDS
    这里的DDS(直接数字合成)是我在MATLAB中用Simulink基本模块搭建起来的模型,仿真DDS信号的产生,并有一个M文件实现与模型同等的功能,MATLAB爱好者一定不要错过(I build the DDS model using simulink basic model to simulate the DDS source, associated a M file realizing the same function as the model,and,the MATLAB lovers must not miss)
    2009-03-14 22:30:17下载
    积分:1
  • base
    1.分别在两个图中画出δ(n)和δ(n-2),其中-10≤n≤10,画出U(n)其中-10≤n≤10。 2.分别在两个图中画出x1(n)=cos(2π×20×0.01×n),0≤n≤10和x2(n)=(0.8)n,1≤n≤6。 3.由上一题,计算y(n)=x1(n)+x2(n),并画图。(1. Draw the figure at two δ (n) and δ (n-2), where-10 ≤ n ≤ 10, draw the U (n) where-10 ≤ n ≤ 10. 2. Respectively in the two Draw the figure x1 (n) = cos (2π × 20 × 0.01 × n), 0 ≤ n ≤ 10 and x2 (n) = (0.8) n, 1 ≤ n ≤ 6. 3. from the previous question, calculate y (n) = x1 (n)+ x2 (n), and drawing.)
    2010-11-26 16:34:06下载
    积分:1
  • Golub_and_Van_Loan.Matrix_computations.pdf
    Matrix - algebra computing. All algorithms in matlab style(Matrix- algebra computing. All algorithms in matlab style)
    2009-06-09 03:25:24下载
    积分:1
  • Bilateral_Filter
    图像处理,双线性滤波器MATLAB程序,经调试可用(Image processing, bilinear filter MATLAB program)
    2014-10-05 20:00:34下载
    积分:1
  • 粗糙度matlab
    计算一维和二维表面粗糙度Ra,根据需要自行选择。(Calculate one and two dimensional surface roughness Ra, according to the needs of your choice.)
    2017-08-01 21:59:44下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载