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andciv 3d printer 控制板常见问题汇总(andciv 3D printer control board QA)

又一个使用ICMP.DLL实现ping的小例子 (Another example of using ICMP.DLL to implement ping)

restores the SDT. an example in c++

接收系统消息不示例,可以提供初学者使用.(receive system message demon .using VC++)

这个程序实现的是素数判别，里边包含两个文件夹(This program is a prime Discriminant inside folder contains two)

VC实现订单管理系统程序源码VC program source code to achieve order management system(VC program source code to achieve order management system)

该程序简单介绍了如何创建局域网的C/S工作模式，简单可靠。(The simple procedure describes how to create LAN C/S mode, simple and reliable.)

Windows串口编程 (Windows serial programming)

设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组，每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。  编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n（n<=200），表示每个数组有n个数。接下来的两行分别是X，Y数组的元素。结果输出 程序运行结束时，将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits.  programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)

网络编程代码，包含UDP,TCP和NET的源码，每种都保护服务器端和客户端(Network programming code, including UDP, TCP and NET source code, each protected server and client)