leidamubiaogenzong

说明：  matlab m语言编写的拼图游戏，对于学习matlab很有帮助-matlab m jigsaw puzzle languages, matlab helpful for learning(matlab m language of the jigsaw puzzle, matlab helpful for learning-matlab m jigsaw puzzle languages, matlab helpful for learning)

求音频的掩蔽曲线,可以用于音频提取水印,还可以用于音频分析(For audio masking curve, can be used for audio watermark extraction can also be used for audio analysis)

追赶法和LU（coolittle） 算法源程序。。。(coolittle algorithm source code)

自适应滤波，利用RLS自适应滤波算法实现信道的均衡，通过Matlab进行编程和仿真(Adaptive filter,use the RLS adaptive filtering algorithm to complete the channel equalization, programming and simulation by Matlab)

swarm algorithm optimization

本文是一片关于FFT的Matlab仿真分析，很具体，配有大量清晰的仿真图片~~有利于FFT初学者的学习(This article is one of the Matlab simulation on the FFT analysis, very specific, clear配有大量simulation picture ~ ~ is conducive to learning for beginners FFT)

雅克比迭代解非齐次线性方程组，逐次求出近似解逼近精确解(Jacobi iterative solution of non-homogeneous linear equations, the successive approximation of the exact solution obtained approximate solution)

对一幅彩色图像进行融合，用到颜色空间转换，数字矩阵到图像显示的转变，同屏显示其效果图，有待进一步研究(Color images of an integration, using the color space conversion, digital matrix image display to change, with the screen display the effect of map, be subject to further study)

最新的基于matlab的tdpca的人脸识别的算别和代码，对人脸识别的有帮助(Based on the latest Matlab tdpca face recognition and other numerical code, Face recognition of the help! !)

在一个移动通信系统中，发射信号是一个未调制的音频x(t)=cos(2πft)，其中f=f0+fi。设标称载波为f0=1GHz，并设fi =512Hz。假定移动用户在一个繁忙的高速公路上距离基站l公里处的地方，从开始从每小时60公里的速度开始，其速度（在0.01秒的时间间隔内测量）以1/2的概率随机的增加或减少1/10公里每小时。试仿真移动用户在这2s的时间间隔内所接收到的信号(及其频谱)。接收信号可以表示为： y(t)=a(t)Cos[2π(fo+f1)(t-△t)] 式中 △(t)=d(t)/c 且 a(t)=k/d2(t) 在上面的表达式中d(t)是在t时刻基站与移动用户的距离，c是光速，△(t)是传播延迟，而a(t)是信号在t时刻的衰减，并假设在这2s内a(t)是一个常数。利用复低通等效模型来进行仿真。(In a mobile communication system, the transmitted signal is an unmodulated audio x (t) = cos (2πft), where f = f0+ fi. Let nominal carrier of f0 = 1GHz, and set fi = 512Hz. Assume that mobile users on a busy motorway station l kilometers place, starting the beginning of 60 kilometers per hour, the speed (measured in 0.01 second interval) to increase the probability of a random 1/2 or reducing 1/10 km/h. Simulation test signal which the mobile subscriber in the 2s time intervals of the received (and its spectrum). The received signal can be expressed as: y (t) = a (t) Cos [2π (fo+ f1) (t- △ t)] Where △ (t) = d (t)/c And a (t) = k/d2 (t) In the above expression, d (t) at time t is a base station and a mobile user s distance, c is the speed of light, △ (t) is the propagation delay, and a (t) is the attenuation of the signal at time t, and assuming that 2s within a (t) is a constant. Using complex low-pass equivalent model for emulation.)