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Matlab-SOR
说明: 计算方法中的SOR算法,根据改变SOR因子的值观察精度变化(Calculation of the SOR algorithm, based on observation of changes in the value of SOR accuracy factor changes)
- 2011-02-23 15:20:26下载
- 积分:1
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matrice_fondamentale_est
matrice fondamentale
- 2013-01-15 02:16:44下载
- 积分:1
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t2cx
生成多个相互独立通道瑞利衰落信道,有两个程序(Generation of single channel Rayleigh channel)
- 2014-12-22 09:50:27下载
- 积分:1
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OFDM
OFDM调制与解调,其中数字调制方式为QPSK。(OFDM modulation and demodulation, the digital modulation method is QPSK.)
- 2020-07-02 06:20:02下载
- 积分:1
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id3
this is the id3 algorithm in matlab, it is the only id3 function which is writen recursively.
- 2009-10-21 16:38:39下载
- 积分:1
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ClassificationParameterState
运用Matlab进行分类、参数估计和状态分析(Classification, parameter estimation and state estimation- An engineering approach using Matlab)
- 2013-10-17 09:20:43下载
- 积分:1
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exa070302
说明如何设计椭圆滤波器及计算和显示功率互补IIR滤波器的频率响应(Explains how to design elliptic filter and the calculation and display of power complementary IIR filter frequency response)
- 2011-12-06 10:47:48下载
- 积分:1
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QPSK--rici
关于QPSK信号经过莱斯信道误码性能分析,有莱斯信道解释及matlab源代码(QPSK signal on the Rician channel error performance analysis, there are Rician channel interpretation and matlab source code)
- 2016-12-18 13:20:47下载
- 积分:1
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ga-MATLAB
说明: 遗传算法MATLAB代码,绝对对你开始学习matlab和遗传算法的人有帮助(MATLAB code of genetic algorithm, the absolute beginning of your learning and genetic algorithm matlab help people)
- 2010-04-13 00:06:46下载
- 积分:1
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ieee754_32
Converts a floating point value to IEEE 754 32 bit binary representation.
Sign Bit: 1
Exp: 2 to 9
Frac: 10:32
Single-precision floating-point format is a computer number format that occupies 4 bytes (32 bits) in computer memory and represents a wide dynamic range of values by using a floating point. In IEEE 754-2008 the 32-bit base 2 format is officially referred to as binary32. It was called single in IEEE 754-1985. In older computers, other floating-point formats of 4 bytes were used.
For example, the 32-bit floating point bit pattern 1 01111101 00101100000000000000000 is interpreted as the following:
(− 1)1 × (1 + 0.34375) × 2(125–127) = -1.34375× 2− 2 = -0.3359375
- 2013-09-07 22:20:32下载
- 积分:1