登录
首页 » matlab » costas_ClosedLoop

costas_ClosedLoop

于 2011-06-14 发布 文件大小:65KB
0 281
下载积分: 1 下载次数: 21

代码说明:

  A Costas loop is a phase-locked loop used for carrier phase recovery from suppressed-carrier modulation signals, such as from double-sideband suppressed carrier signals. It was invented by John P. Costas at General Electric in the 1950s. Its invention was described as having had "a profound effect on modern digital communications".

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • KalmanFilteringandNavigationPrinciples
    卡尔曼滤波与组合导航原理,非常适合初学者了解原理(Kalman filtering and navigation principles, the principle is very suitable for beginners to understand)
    2010-10-14 10:54:16下载
    积分:1
  • chapter7
    Anderson 计算流体力学入门第七章的第一个程序(the first program for Anderson Computational Fluid Dynamics )
    2013-04-06 21:34:50下载
    积分:1
  • ajay-task2
    code encryption and decryption using matlab
    2015-02-24 19:05:41下载
    积分:1
  • Hamming-Code
    汉明码经过bsc信道的变换,设计比较经过编码与非编码的两种情况,统计了错误图样,适合本科生学习信息论与编码借鉴使用。为matlab工具开发。(Hamming Code across bsc)
    2014-01-24 19:20:05下载
    积分:1
  • matlab与纵联差动保护的结合
    matlab与纵联差动保护的结合,精确计算,工程应用。(matlab combination with longitudinal differential protection, accurate calculation, engineering applications.)
    2021-03-07 20:29:29下载
    积分:1
  • CHAP5
    图像增强技术 直方图增强 几种空间域滤波相应的matlab代码(Several spatial domain filtering technology histogram of image enhancement corresponding matlab code)
    2014-09-10 15:49:51下载
    积分:1
  • OD1
    基于神经网络估算断面客流量与出行量之间的OD矩阵(OD matrix estimation section between the amount of traffic and travel based on neural network)
    2014-09-12 16:22:31下载
    积分:1
  • cal_kr_dfe
    基于standford大学cioffi教授的经典算法,计算有线信道的最佳判决反馈滤波器系数。(Calculate the optimal DFE coeffients based on the algorithm propoased by prof. Cioffi)
    2014-09-19 17:59:48下载
    积分:1
  • contourlet
    contourlet方法源代码,实现对图像特征值的提取(code of contourlet method)
    2011-10-03 17:43:57下载
    积分:1
  • Fast-fourier-Transform
    to find the discrete fourier transform using the fast fourier algorithm, any sequence of lengths which are multiples of 2 simply append zeros to satisfy this requirement
    2013-12-04 00:13:33下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载