登录
首页 » matlab » canny2

canny2

于 2011-06-03 发布 文件大小:1KB
0 199
下载积分: 1 下载次数: 1

代码说明:

  canny operator for edge detection

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • POURSUITE
    backstepping applied to tracking problem of a marine vehicle
    2011-05-27 00:27:08下载
    积分:1
  • subma
    最近搞设计弄来的一些资料 大家一起参考 基于matlab伪随机序列产生(engage recently obtained some design information together reference Matlab-based pseudo-random sequence generation)
    2007-06-13 18:50:39下载
    积分:1
  • 00
    说明:  主成分析在matlab中应用有源程序,关于主要因素的提取(Principal Component Analysis in matlab application has source code, the main factors on the extraction)
    2008-05-26 02:49:42下载
    积分:1
  • PTS
    PTS算法降低ofdm系统中的峰均功率比(PTS algorithm reduces PAPR ofdm system)
    2011-01-08 20:47:53下载
    积分:1
  • loadflow
    Load flow: This file is to solve the load flow problem in power systems
    2012-04-09 03:18:03下载
    积分:1
  • Double_LooP
    直流电机转速电流双闭环matlab仿真模型(DC motor speed current double closed loop matlab simulation model)
    2013-04-16 18:19:26下载
    积分:1
  • The_Big_Bang_Theory---season-2.en
    THIS IS THE SUBTITLE FILE OF ONE OF THE MOST POPULAR TV SHOW BIGBANG THEORY
    2015-04-05 11:26:46下载
    积分:1
  • MATLABd7481ae000b0f00ea
    MATLAB程序设计与应用 MATLAB程序设计与应用 MATLAB程序设计与应用 MATLAB程序设计与应用 MATLAB程序设计与应用(MATLAB Program Design and Application MATLAB Program Design and Application MATLAB Program Design and Application MATLAB Program Design and Application MATLAB Program Design and Application MATLAB Program Design and Application MATLAB Program Design and Application MATLAB Program Design and Application)
    2011-04-26 19:14:25下载
    积分:1
  • huizhiquxian
    在同一坐标内,分别用不同线型和颜色绘制曲线y1=0.2e-0.5xcos(4πx) 和y2=2e-0.5xcos(πx),标记两曲线交叉点。( In the identical coordinates, separately uses different linear and color curve y1=0.2e-0.5xcos (4 pi x) and y2=2e-0.5xcos (pi x), marks two curves intersections. )
    2006-06-06 12:06:57下载
    积分:1
  • xiaobo1
    sin函数的简单一维小波变换与一维傅里叶变换的比较算法(sin function with a simple one-dimensional wavelet transform one-dimensional Fourier transform of the comparison algorithm)
    2013-10-03 09:49:42下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载