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Midamble_Generation
这是gsm系统中midable数据生成的代码matlab仿真程序,上传给大家学习和参考。(This is a gsm system midable data generated code matlab simulation program, upload for everyone to study and reference.)
- 2010-05-05 20:49:51下载
- 积分:1
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DVHop
无线传感器网络中距离无关的定位算法DVHOP的简单程序,有注释,可调试。(Wireless sensor network localization algorithm DVHOP from unrelated simple program, there are notes, can be debugged.)
- 2013-08-25 15:51:43下载
- 积分:1
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iut...BallonBeamcontrol
Ball on Beam Controller Matlab m.file and simulink.(1)
- 2009-10-08 19:44:27下载
- 积分:1
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1
说明: 后联平滑滤波器的卡尔曼滤波器的使用,这个代码很不错的哦(After the joint smoothing filter is the use of the Kalman filter, this code is very good Oh)
- 2012-06-13 11:55:25下载
- 积分:1
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DCT
this function block an Arbitrary image and take dct from each block.
for check quality of reconstructed image calculated PSNR.
- 2013-08-04 15:18:29下载
- 积分:1
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123
微弱信号的检测和提取,用MATLAB语言实现,包括了小波法(Weak signal detection and extraction, using MATLAB language, including the wavelet method)
- 2011-11-06 19:04:32下载
- 积分:1
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recordandvoice
用matlab实现录音放音,播放祝你生日歌,附说明文档。。(Implementation of audio playback using MATLAB, player I wish you a birthday song, with documentation)
- 2015-03-06 16:07:52下载
- 积分:1
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zltz
实现增量调制的简单的程序,十分简短。你应该可以作得更好(delta modulation to achieve the simple procedure is very short. You should be able to do better)
- 2006-06-02 18:14:35下载
- 积分:1
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PID
灰色PID控制。灰色系统理论,PID控制。是灰色模型GM进行定量预测(Grey PID control. Grey system theory, a PID control. Grey model GM quantitative prediction)
- 2012-04-09 20:35:50下载
- 积分:1
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ieee754_32
Converts a floating point value to IEEE 754 32 bit binary representation.
Sign Bit: 1
Exp: 2 to 9
Frac: 10:32
Single-precision floating-point format is a computer number format that occupies 4 bytes (32 bits) in computer memory and represents a wide dynamic range of values by using a floating point. In IEEE 754-2008 the 32-bit base 2 format is officially referred to as binary32. It was called single in IEEE 754-1985. In older computers, other floating-point formats of 4 bytes were used.
For example, the 32-bit floating point bit pattern 1 01111101 00101100000000000000000 is interpreted as the following:
(− 1)1 × (1 + 0.34375) × 2(125–127) = -1.34375× 2− 2 = -0.3359375
- 2013-09-07 22:20:32下载
- 积分:1