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MSE_compare
信道估计的几个算法比较(matlab源代码)(Several channel estimation algorithm for comparison)
- 2009-09-19 11:02:50下载
- 积分:1
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rbfapproximation
rbf neural network approximation
- 2010-01-14 22:10:31下载
- 积分:1
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A-robust-system
说明: 一种鲁棒的电子稳像系统,很有用处,帮助很大!(A robust electronic image stabilization system, very useful, very helpful!)
- 2011-04-17 11:29:00下载
- 积分:1
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matlab_picture_processing
matlab图形处理,可处理灰度,彩色图形,对图形进行各种变换,添加噪音,滤波处理等(matlab graphics processing, processing grayscale, color graphics, various changes to the graphics, add noise filtering process)
- 2013-04-29 11:27:42下载
- 积分:1
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1
说明: 全有全无配流法,用于交通分配之用,为交通分配的最为基础的分配方法(All have nothing assignment method, used for traffic assignment, traffic distribution for the allocation of the most basic)
- 2011-03-25 18:31:34下载
- 积分:1
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Discrete-Fourier-Transform-2D
Implementation of Discrete fourier transform 2D (to images )
- 2013-12-04 12:26:45下载
- 积分:1
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watermarkingg
this code implements a new watermarking method
- 2010-10-27 17:42:58下载
- 积分:1
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Neural-network
一种基于神经网络模型的matlab实现程序(Based on neural network model matlab implementation procedures)
- 2010-02-02 15:46:05下载
- 积分:1
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chap3
说明: 程序代码说明
P0301:数字图像矩阵数据的显示及其傅立叶变换
P0302:二维离散余弦变换的图像压缩
P0303:采用灰度变换的方法增强图像的对比度
P0304:直方图均匀化
P0305:模拟图像受高斯白噪声和椒盐噪声的影响
P0306:采用二维中值滤波函数medfilt2对受椒盐噪声干扰的图像滤波
P0307:采用MATLAB中的函数filter2对受噪声干扰的图像进行均值滤波
P0308:图像的自适应魏纳滤波
P0309:运用5种不同的梯度增强法进行图像锐化
P0310:图像的高通滤波和掩模处理
P0311:利用巴特沃斯(Butterworth)低通滤波器对受噪声干扰的图像进行平滑处理
P0312:利用巴特沃斯(Butterworth)高通滤波器对图像进行锐化处理(Procedure Code Description P0201: MATLAB assignment P0202: MATLAB in the for loop P0203: MATLAB in the for loop and if condition P0205: MATLAB image processing basics P0206: MATLAB high-level image processing operations P0207: RGB image created according to a gray image P0208: binary image of the check against action P0209: use the imshow function to display images P0210: in the same window display two images)
- 2010-04-11 22:19:09下载
- 积分:1
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adms4
用Admas四阶预估-校正算法的PECE模式求下列初值问题的数值解,步长h=0.1。(with Adams estimated four bands- correction algorithm PECE following initial model for the numerical solution of the problem, Step-h = 0.1.)
- 2006-05-27 00:01:41下载
- 积分:1