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使用C#监听刷卡器，调用rest服务获取打印任务，解析并调用打印机打印(Use C# to listen swipe card reader, calls the rest service get the print job, resolve and call the printer)

一个打印表格的c++源代码，对于那些寻找此类代码的同志来说，是一个绝佳的参考，如果有什么问题，登陆http://www.boomcode.cn(A print form c++ Source code, for those looking for such code comrades, it is an excellent reference, if there is any problem, landing http://www.boomcode.cn)

VC++　用MFC编写的打印程序，希望对大家有用(VC++ MFC Print)

带宽测试工具，用于测试网络带宽的峰值，直接在屏幕打印结果。(Bandwidth testing tool)

实现带头结点的单向链表的创建、删除链表、插入结点等操作，并能实现年龄递增的两个单向链表合并一个链表，合并后的链表按年龄递减，可认为同名同年龄是同一个学生，每个学生在合并后的链表中仅出现一次。最后打印输出合并后的链表元素，验证结果的正确性(Take the lead node singly linked list to create, delete linked list, insert node operation, and age of increasing two-way linked list merge a linked list, combined linked list decreasing by age, with the same name in the same age a student, each student appears only once in the combined list. The final printout list elements after the merger, the correctness of the verification results)

用TCL/TK实现4幅字符串图片的动态输出，图片为圣诞老人像(Realize outputing four pictures.)

用C语言实现的各种小程序，例如搬砖问题、打印图形等等。(Using C language implementation of a variety of small programs, such as moving bricks problem, print graphics and so on.)

使用C#开发的多种方式 打印PDF文件，包括O2S，命令行等。(Using C# to develop multiple ways to print PDF files, including O2S, command line, etc.)

andciv 3d printer 控制板常见问题汇总(andciv 3D printer control board QA)

题目：打印出杨辉三角形（要求打印出10行题目：输入3个数a,b,c，按大小顺序输出。 题目：输入数组，最大的与第一个元素交换，最小的与最后一个元素交换，输出数组。 题目：有n个整数，使其前面各数顺序向后移m个位置，最后m个数变成最前面的m个数 题目：编写一个函数，输入n为偶数时，调用函数求1/2+1/4+...+1/n,当输入n为奇数时，调用函数1/1+1/3+...+1/n(Topic: Print out the Triangle (10 lines required to print out the Title: Enter the 3 numbers a, b, c, according to the order of output. Title: input array, the largest exchange with the first element, the smallest and the last element of the exchange, output array. Topic: There are n integers, to move back in front of the order m of the number of positions, finally becoming the foremost m m the number of number of topics: write a function, the input n is even, the call function evaluation 1/2+1/4+...+ 1/n, when the input n is odd, call the function 1/1+1/3+...+ 1/n)