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ginput2
Do you still use GINPUT to graphically select points on current axes with the mouse? Try this one!
With GINPUT2 you can also:
1. ZOOM: in, out (double-click)!
2. PAN: when dragging!
3. DELETE: last selected point!
4. PLOT: while selecting! (optional, just input the line style!)
5. SCALE or GEOREFERENCE images! (optional, just input: true)
So, besides of selecting points in a more precise way (zooming) you can DIGITIZE(!!!) lines with the last two options, by simply using:
>> ginput2(true, .k )
Enjoy it!
- 2010-02-17 07:17:07下载
- 积分:1
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panel-(1)
A hess and smith panel method code for aerofoil analysis
- 2013-05-26 23:31:43下载
- 积分:1
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emd_toolbox
EMD工具箱,不仅包含源程序,而且有例子,适合初学者。(EMD toolbox)
- 2010-11-11 23:43:48下载
- 积分:1
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Basic-concept-in-matlab
basic concept in matlab
- 2015-02-19 16:47:33下载
- 积分:1
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Gaussian_interpolation
插值算法,具体使用方向为高斯插值,Kriging插值可以参考(Interpolation algorithm, the specific direction of the Gaussian interpolation, Kriging interpolation can refer to)
- 2010-12-08 12:42:56下载
- 积分:1
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rcosflt_Jamming
1、根据干扰总功率要求,在PSK调制信号带宽内产生单音干扰和多音干扰信号,并叠加到产生的信号源上。
2、将收到干扰的信号进行频率搬移到基带,然后通过匹配滤波器以及解调过程得到信息,统计误码率并与真实信息的解调误码率进行对比,评估音频干扰对PSK信号的干扰效果。
(1, according to the total power requirement of interference generated tone signal interference and multi-tone interference in the PSK modulated signal bandwidth, and superimposed on the signal generated by the source. 2, the received interference signal to a baseband frequency shift, and the information obtained by the matched filter and a demodulation process, statistical error rate BER and the true information demodulation comparison, evaluation of the PSK signal, audio interference interference effects.)
- 2014-05-03 13:20:55下载
- 积分:1
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MPU6050
MPU6050_Arduino 计算三轴陀螺仪的姿态变换计算其角度(MPU6050_Arduino calculate the three-axis gyroscope attitude transformation to calculate the angle)
- 2014-05-07 21:36:46下载
- 积分:1
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bootstrap
英国剑桥出版社出版的bootstrap一书的附录程序(Cambridge, England published a book on the bootstrap procedure in Appendix)
- 2007-10-11 16:09:55下载
- 积分:1
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5
一道程序编译顺序的考题,涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。
C的程序编译总是从main函数开始的,这道题的重点在“fun((int)fun(a+c,b),a-c)) ”语句。
系统首先要确定最外层 fun()函数的实参,第一个参数的确定需要递归调用fun()函数(不妨称其为内层函数)。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)
- 2009-03-15 15:36:23下载
- 积分:1
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radar_codes_matlab
radar equation for target estimation
- 2009-05-25 02:21:43下载
- 积分:1