登录
首页 » Visual C++ » niudun

niudun

于 2011-05-14 发布 文件大小:1KB
0 321
下载积分: 1 下载次数: 3

代码说明:

  牛顿下山算法 牛顿迭代算法 和牛顿差值多项式 (Newton downhill method the difference between Newton and Newton polynomial algorithm)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • 570486690TDIDF_Demo
    TFIDF计算方法详细解释,代码解释很多,也有帮助文档(TFIDF calculation method explained in detail, explain a lot of code, but also help documentation)
    2015-04-03 10:18:35下载
    积分:1
  • medfilt_avefile_bijiao
    Matlab实现中值滤波与均值滤波的对椒盐噪声滤波的比较!(Matlab to achieve median filter and mean filter for noise filtering salt and pepper comparison!)
    2009-06-06 20:30:19下载
    积分:1
  • HYHY
    VC++调Matlab的简易程序,调出Matlab的figure图(VC++ tune simple Matlab program, bring up Matlab' s figure diagram)
    2009-12-14 16:59:51下载
    积分:1
  • source
    This derivation of the normalised least mean square algorithm is based on Farhang- Boroujeny 1999, pp.172-175, and Diniz 1997, pp 150-3. To derive the NLMS algorithm we consider the standard LMS recursion, for which we select a variable step size parameter, μ(n). This parameter is selected so that the error value , e+(n), will be
    2011-01-12 17:04:12下载
    积分:1
  • fiber-EH11-mode
    利用matlab模拟光纤中EH11模的模式分布图。(Using matlab simulation mode fiber EH11 mode maps.)
    2020-07-03 17:00:01下载
    积分:1
  • 3D
    说明:  自动生成三维的多孔介质,对多孔介质研究的学者有用(Automatic generation of three-dimensional porous media, porous media studies scholars Useful)
    2015-10-01 13:54:48下载
    积分:1
  • Desktop
    室内环境射线跟踪算法研究,这是对室内环境建模(Indoor Environment Research ray tracing algorithm, which is modeled on the indoor environment)
    2014-02-23 20:57:04下载
    积分:1
  • zcgzxl
    最长公共子序列的 c代码,可以直接运行获得结果。(C code for the longest common subsequence can be run directly.)
    2013-12-04 16:13:33下载
    积分:1
  • friendtest4
    有关友元函数,对于初学者是一个非常不错参考例子(friend )
    2009-11-30 19:36:03下载
    积分:1
  • public
    Base64编码说明 Base64编码要求把3个8位字节(3*8=24)转化为4个6位的字节(4*6=24),之后在6位的前面补两个0,形成8位一个字节的形式。 如果剩下的字符不...(Base64-encoded instructions require the Base64 encoding three 8-bit bytes (3* 8 = 24) was converted to 4 6 bytes (4* 6 = 24), then in front of the two s complement 6 0, 8 is formed bits in a byte form. If the rest of the characters do not ...)
    2015-03-18 17:44:08下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载