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matlab
Matlab图像各点坐标值和灰度值的表示,图像分割(Matlab image points coordinates and gray value representation, image segmentation)
- 2011-09-13 16:49:07下载
- 积分:1
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Final-project
利用matlab 制作GUI系统 模拟并分析LTE 基站的功效与多种调制方式之间的配合 从而得出最优化方案。 (Produced using matlab GUI system simulation and analysis of the effectiveness of LTE base station with a variety of co-ordination between the modulation and thus finding the most optimal solution.
discription:
1.At the beginning ,the Base Station covers 20 UEs ,each uses 5 RBs
2.the new UE inserts to the system would also use 5RB
3.the total resource for the system : 100 RBs)
- 2011-10-07 00:07:27下载
- 积分:1
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FastCIA
FastICA 快速独立成分分析 源码、实例(IndependentComponentAnalysis )
- 2013-08-21 20:42:03下载
- 积分:1
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BIO
This is the code for IRIS recognition by masek.It includes all the files including description of MASEK thesis.
- 2009-11-23 07:33:32下载
- 积分:1
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ICA
说明: 独立分量分析代码(matlab编写)有很强的试用价值(Independent Component Analysis code (matlab preparation) has a very strong trial value)
- 2020-11-05 13:19:51下载
- 积分:1
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MATLAB-statistics-40cases
matlab统计分析的40个案例分析,欢迎交流(matlab statistical analysis of 40 case studies, welcomed the exchange)
- 2011-06-21 16:37:18下载
- 积分:1
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Matlab-mathematical-modeling
matlab 数学建模与应用 适用于已经入门的matlab用户(matlab mathematical modeling and application has been started for matlab users)
- 2011-11-11 21:10:40下载
- 积分:1
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nonstationary-random-signal-WVD
此例程为配套书籍的第六章例题6-5的相对应代码,功能为计算非平稳随机信号的WVD时频谱,编程环境为matlab。(This routine matching books Chapter Example 6-5 corresponding to the code for the calculation of the non-stationary random signal WVD spectrum programming environment for matlab.)
- 2013-05-02 18:49:44下载
- 积分:1
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RQA
Recurrence quantification analysis (RQA) of recurrence plots (RPs)
- 2021-04-14 15:28:55下载
- 积分:1
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mini2
clear all
clc
t=0:1/1000:10-1/1000
s=sin(2*pi*t)
snr=20
s_power=var(s) varience of s
linear_snr=10^(snr/10)
factor=sqrt(s_power/linear_snr)
noise=randn(1,length(s))*factor
x=s+noise Ó É SNR¼ Æ Ë ã Ë æ » úÔ ë É ù
x1=noise Ô ë É ùÔ ´ Ê ä È ë
x2=noise
w1=0 È ¨Ï µ Ê ý ³ õ Ö µ
w2=0
e=zeros(1,length(x))
y=0
u=0.05
for i=1:10000 LMSË ã ·¨
y(i)=w1*x1(i)+w2*x2(i)
e(i)=x(i)-y(i)
w1=w1+u*e(i)*x1(i)
w2=w2+u*e(i)*x2(i)
end
figure(1)
subplot(4,1,1)
- 2010-10-26 16:41:03下载
- 积分:1