guasMATLAB

MATLAB的梯度法源程序，按照提示输入，可直接运行(MATLAB source code of the gradient method, in accordance with the prompt input, can be directly run)

说明：  一篇关于matlab命令的学习文档，很适合初学者，我是新手还没有太多这方面的源码，只好自己手头的学习资料和大家分享(A study document on the matlab command, it is suitable for beginners, I am a novice in this area have not so much the source, but to their own learning materials on hand to share)

基于MATLAB 的线性系统极点配置问题的算法分析。本文分析了基于龙伯格能控规范型的极点配置问题的算法，并写出在matlab环境下的算法程序(linear system pole configure)

在对比度小的灰度图像中加入噪声，再对图像进行滤波和直方图均衡化，对图像进行增强，并比较了不同参数时的增强效果(In contrast, the gray image by adding a small noise, then the image filtering and histogram equalization of image enhancement, and compared the effect of different parameters of the enhanced)

MATLAB语言精要及动态仿真工具SIMULINK(Essentials of MATLAB language and SIMULINK dynamic simulation tool)

基于MUSIC的DOA估计，算法简单较为快捷可以修改(easimation of DOA)

某市有一码头，每次仅容一辆船停泊装卸货，由于经常有船等候进港，部分人提出要扩建码头。经过调查历史资料发现，码头平均每月停船24艘，每艘船的停泊时间为24±20小时，相邻两艘船的到达时间间隔为30±15小时，如果一艘船因有船在港而等候1小时，其消耗成本为1000元。经预算，扩建码头大约需要1350万元，故市长决策如下：如果未来五年内停泊船只因等候的成本消耗总和超过扩建码头花费则扩建码头，否则，不予扩建。因此，希望你能够帮助市长做出决策。此问题已知到达的大概时间和大概停泊时间，对于此问题用概率统计的方法来做比较复杂，可用程序随机产生到达时间和停泊时间来模拟未来五年内船的停泊，多次模拟预测停泊情况，以做出决策(。-Problem in a city with a terminal expansion dock, each only allow a boat moored loading and unloading, as often there are waiting boat into port, some people proposed to expand pier. Terminal stopping 24 per month, per vessel berthing time of 24 ± 20 hours, the arrival of two adjacent vessels interval 30 ± 15 hours, if a ship due to boat in the harbor while waiting for one hour, and its consumption cost of 1,000 yuan. The budget of about 13.5 million yuan expansion dock, so the mayor decision as follows: If a ship is moored next five years, the cost of waiting more than the sum of consumption spending is expanding marina pier extension, otherwise, not expanded.)

JSONArray的使用 附带程序注释与输出(JSONArray use with program notes and output)

Matlab中用GUI设计一简单计算器。(err)

系统的介绍了MATLAB软件，并用该语言解决了大量的编程问题。(Systematic introduction of the MATLAB software, and use the language to solve a lot of programming problems)