matlab--zigzag

matlab 自适应LFM源程序，有仿真图形，非常好。(matlab adaptive LFM source, a simulation of graphics, very good.)

MATLAB HELP FUNDENMENTAL IN YOUR CODE FOR HELPING

用MATLAB GUI自制的时钟，可以实现自动计时。(MATLAB GUI with homemade clock, can achieve automatic timing.)

Returns weighted percentiles of a sample given the weight vector w ％ The idea is to give more emphasis in some examples of data as compared to ％ others by giving more weight. For example, we could give lower weights to ％ the outliers. ％ The motivation to write this function is to compute percentiles for Monte ％ Carlos simulations where some simulations are very bad (in terms of goodness ％ of fit between simulated and actual value) than the others and to give ％ the lower weights based on some goodness of fit criteria.(Returns weighted percentiles of a sample given the weight vector w The idea is to give more emphasis in some examples of data as compared to others by giving more weight. For example, we could give lower weights to the outliers. The motivation to write this function is to compute percentiles for Monte Carlos simulations where some simulations are very bad (in terms of goodness of fit between simulated and actual value) than the others and to give the lower weights based on some goodness of fit criteria .)

OFDM simulation for matlab with 4 qam

Gabor变换属于加窗傅立叶变换，Gabor函数可以在频域不同尺度、不同方向上提取相关的特征。另外Gabor函数与人眼的生物作用相仿，所以经常用作纹理识别上，并取得了较好的效果。(Gabor transform is windowed Fourier transform, Gabor functions in the frequency domain at different scales and different directions to extract relevant features. Gabor function and other biological effects similar to the human eye, so often used as a texture on the identification, and have achieved good results.)

广义互相关时延估计，瑞利限广义互相关时延估计，瑞利限广义互相关时延估计，瑞利限(Generalized cross-correlation delay estimation, generalized Rayleigh limit cross-correlation delay estimation, generalized Rayleigh limit cross-correlation delay estimation, the Rayleigh limit)

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)

三阶倒立摆的鲁棒控制算法，包含了H infinity control 和mu analysis 算法，并进行了比较，很好的程序，值得分享。(Robust order inverted pendulum control algorithm, including the H infinity control and mu analysis algorithm, and compared, a very good program, worth sharing.)

基于双树小波通用隐马尔可夫树模型的图像压缩感知(Compressive Sensing for Image Using Orthogonal Wavelet Transform and Orthogonal Matching Pursuit Algorithm)