Fig2a

A mathmatical model of biology(A mathmatical model for ATM response)

我们学校学报上一篇关于多信号MS模型仿真的matlab仿真设计的文章，里面的思想很有值得借鉴之处。(Our school s paper, a multi-signal MS model simulation using matlab.A good design idea.)

A. Fusion at the Feature Extraction Level The data obtained from each sensor is used to compute a feature vector. As the features extracted from one biometric trait are independent of those extracted from the other, it is reasonable to concatenate the two vectors into a single new vector. The primary benefit of feature level fusion is the detection of correlated feature values generated by different feature extraction algorithms and, in the process, identifying a salient set of features that can improve recognition accuracy [14]. The new vector has a higher dimension and represents the identity of the person in a different hyperspace. Eliciting this feature set typically requires the use of dimensionality reduction/selection methods and, therefore, feature level fusion assumes the availability of a large number of training data.

说明：  采用平面波展开法计算2维光子晶体的能带图(The plane wave expansion method two-dimensional photonic crystals with map)

《高等光学仿真》第一版的matlab源程序(" Advanced optical simulation," the first edition of matlab source)

Autonomous Robotics Mobile Robot Kinematics

说明：  龚纯主编的“matlab语言常用算法程序集”的第6章 源代码(Gong pure edited " matlab language commonly used algorithm for assembly," Chapter 7 source code)

写一个MATLAB程序，实现4个时间同步的CDMA用户的仿真，其中每个用户都使用长度为L=31的不同的Gold序列。每个用户都采用它们代表的Gold序列的二进制（+-1）调制。每个用户的接收端将这个复合的CDMA接收信号相关，而这个复合的信号都在它们各自的序列上受到AWGN的污损（基于按码片相加）。在N=10000信息比特下，仿真估值并画出作为SNR的函数的CDMA通信系统的差错概率。(Write a MATLAB program, the realization of the four time synchronization of the simulation of CDMA users, including the length of each user for use of the L = 31 different Gold sequences. They are used for each user on behalf of the Gold sequence of binary (+-1) modulation. Each user' s receiver will receive the composite CDMA signal, and this composite signal in the sequence of their respective defaced by the AWGN (additive based on the chip by). Information in the N = 10000 bits, the simulation value and draw as a function of SNR of the CDMA communication system the probability of error.)

hydraulic spring

题目：有1、2、3、4个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？ 1.程序分析：可填在百位、十位、个位的数字都是1、2、3、4。组成所有的排列后再去 　　　　　　掉不满足条件的排列。 (Title: There are numbers 1,2,3,4, how many can be composed of distinct three-digit numbers without repetition? Is how much? 1. Program Analysis: fill in the hundred, ten, a bit of the numbers are 1,2,3,4. Composed of all the permutations and then remove the arrangement does not meet the conditions.)