pda_matlab

无限大藏储试井分析图版，分析无因次压力变化以及导数变换(Infinite reservoir in well test analysis Plate)

说明：  基于matlab 潮流计算的程序代码 (matlab )

这是基于PCA的人脸识别代码,识别率达到88.5 ,比较理想,希望对大家有所帮助.(This is a PCA-based face recognition code, the recognition rate of 88.5 , ideal, we want to help.)

TREES PROGRAM IMPLEMENTAION DATA STRUCTRES

使用MATLAB实现的基于多类别的KNN算法，简称为MLKNN(Using MATLAB to achieve KNN algorithm based on multi-category, referred to as MLKNN)

说明：  使用各种方法进行图像特征提取，对特征不明显的图像有很好的效果！(Using a variety of methods for image feature extraction, feature obscure the image of good results!)

matlab逆broyden迭代法计算方程(Matlab broyden inverse iteration calculation equation)

统计信号处理基础完整 经典教材习题解答 作者手写扫描 包含检测理论与估计理论两个部分(Complete statistical signal processing base Classic textbook exercises answers Author scanned handwritten Consists of two parts detection theory and estimation theory)

SER算法在自适应中的应用代码，其程序简单，但效果很好，可以和LMS算法做对比实验。(SER algorithms in adaptive application code, the procedure is simple, but the effect is very good, and the LMS algorithm to do comparative experiments.)

在一个移动通信系统中，发射信号是一个未调制的音频x(t)=cos(2πft)，其中f=f0+fi。设标称载波为f0=1GHz，并设fi =512Hz。假定移动用户在一个繁忙的高速公路上距离基站l公里处的地方，从开始从每小时60公里的速度开始，其速度（在0.01秒的时间间隔内测量）以1/2的概率随机的增加或减少1/10公里每小时。试仿真移动用户在这2s的时间间隔内所接收到的信号(及其频谱)。接收信号可以表示为： y(t)=a(t)Cos[2π(fo+f1)(t-△t)] 式中 △(t)=d(t)/c 且 a(t)=k/d2(t) 在上面的表达式中d(t)是在t时刻基站与移动用户的距离，c是光速，△(t)是传播延迟，而a(t)是信号在t时刻的衰减，并假设在这2s内a(t)是一个常数。利用复低通等效模型来进行仿真。(In a mobile communication system, the transmitted signal is an unmodulated audio x (t) = cos (2πft), where f = f0+ fi. Let nominal carrier of f0 = 1GHz, and set fi = 512Hz. Assume that mobile users on a busy motorway station l kilometers place, starting the beginning of 60 kilometers per hour, the speed (measured in 0.01 second interval) to increase the probability of a random 1/2 or reducing 1/10 km/h. Simulation test signal which the mobile subscriber in the 2s time intervals of the received (and its spectrum). The received signal can be expressed as: y (t) = a (t) Cos [2π (fo+ f1) (t- △ t)] Where △ (t) = d (t)/c And a (t) = k/d2 (t) In the above expression, d (t) at time t is a base station and a mobile user s distance, c is the speed of light, △ (t) is the propagation delay, and a (t) is the attenuation of the signal at time t, and assuming that 2s within a (t) is a constant. Using complex low-pass equivalent model for emulation.)