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a_novel_timing_and_frequency_synchronization_algor
一种基于PN训练序列的OFDM时频同步的新算法。通过构造倒序结构的同步训练序列,获得了较好的定时性能。(PN training sequence based on the OFDM time-frequency synchronization of the new algorithm. By constructing a reverse structure synchronization training sequence, to obtain a better performance from time to time.)
- 2008-06-28 10:36:40下载
- 积分:1
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1
说明: matlab code for JTAG cable checking
- 2014-02-04 19:27:39下载
- 积分:1
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All-phase--correction-method
全相位时移相位差频谱校正法的文章,帮助大家学习。(All phase shift the phase spectrum correction method, article, and help them to learn)
- 2012-04-25 15:30:44下载
- 积分:1
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adp_spa_denoise
基于个数判断脉冲噪声的中值滤波器在matlab下的仿真实现,整个程序可以运行(adp_spa_denoise)
- 2009-03-27 17:20:22下载
- 积分:1
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598752watermark
数字水印毕业论文好材料,希望对大家毕业设计有所作用(Good material digital watermark Thesis)
- 2010-05-25 01:09:48下载
- 积分:1
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A-fuzzy-algorithm----Matlab
在matalb中使用模糊控制器对机器人避障进行仿真(Robot Obstacle Avoidance Base on Application of Fuzzy Algorithm)
- 2021-04-19 11:08:51下载
- 积分:1
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PV
说明: 光伏阵列最大功率跟踪系统(光伏电池模型+扰动观察法+BOOST电路)simulink仿真系统。((PV system to achieve maximum power tracking via a boosconverters, and the control method is perturbation and observation))
- 2018-04-15 17:46:35下载
- 积分:1
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Matlab
《MATLAB7.0从入门到精通》全书源码,包括使用说明。(MATLAB7.0 From Novice to Professional book source code, including instructions for use.)
- 2010-09-16 16:43:34下载
- 积分:1
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proy2
practice system operating
- 2009-12-02 13:48:51下载
- 积分:1
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Chapter6
数值解法
例1 用改进的欧拉方法求一阶方程初值问题的
数值解
例2 数学摆的运动方程与近似方程数值解比较
例3 四阶龙格库塔公式求数值解
Matlab实现求数值解
例1 求初值问题y =x*sin(x)-y,y(0)=0的数值
解.先编辑一个定义方程的ODEF函数文件
ODEfun1.m.
例2 求方程组初值问题的数值解,按指定步长
0.05划分节点.
例3 按指定的精度求高阶方程初值问题的数值解.(Numerical Solution of the law a method of using the improved Euler' s equation of order to a first-order initial value problem of the numerical solution of cases of two mathematical pendulum equations of motion compared with the approximate numerical solutions of equations of three cases of fourth-order Runge-Kutta numerical solution of the formula Matlab order to achieve the numerical solution of demand cases seeking an initial value problem y ' = x* sin (x)-y, y (0) = 0 the numerical solution. first, the definition of an equation editor ODEF function file ODEfun1.m. cases of two demand equations initial value problem of numerical solution, according to the specified division of the node step 0.05. Example 3 according to the specified precision of seeking higher-order equation of the numerical solution of initial value problem.)
- 2010-02-05 23:14:41下载
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