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exercise

于 2010-05-09 发布 文件大小:1KB
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代码说明:

  根据公式I(n-1)=(1-In)/n 令I11=0计算I1 到I10; 根据公式In=1-nI(n-1) 令I0=0.6321 计算I1到I7; 根据公式X2=a , 令a=2,计算X的值。(According to the formula I(n-1)=(1-In)/n ,set I11 equals zero,and count I1 to I10. According to the formula In=1-nI(n-1),set I11 equals zero,and count I1 to I10. According to the formula X square equals a ,set a equals two ,then calculate X )

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