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Test_Code1
已知一个序列x(n)=0.5cos(0.55*pi*n)+cos(0.45*pi*n),时域FFT分析其频谱。
(1)使用不同宽度的矩形窗截断该序列为M点,取M分别为:20,40,160,观察不同长度对频谱影响;(2)使用哈明窗和凯泽窗重做;(3)对三种窗的结果进行分析比较;(4)总结窗类型和长度对频谱分析的影响。
(Known a sequence x (n) = 0.5cos (0.55* pi* n)+ Cos (0.45* pi* n), time-domain FFT analysis of its spectrum. (1) use a different width of the rectangular window of the sequence for M cut-off point, take M are as follows: 20,40,160, observing the impact of different lengths of the spectrum (2) the use of Hamming window and the Kaiser window redo (3 ) on the three windows analyzed and compared the results (4) summarize the type and length of window for spectrum analysis.)
- 2007-10-30 17:08:01下载
- 积分:1
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images
images of fishes for claassifyication
- 2013-02-03 22:59:19下载
- 积分:1
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speckle-noise
数字图像滤波的程序,包括散斑噪声的生成,中值,均值,Lee,Kuan滤波算法的实现,还计算了三个指标:峰值信噪比,等效视数,散斑指数。(Digital image filtering process, including the generation of speckle noise, median, mean, Lee, Kuan filtering algorithm, also calculated three indicators: the peak signal to noise ratio, equivalent number, speckle index.)
- 2014-04-08 21:18:34下载
- 积分:1
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dea matlab
求解DEA CCR BCC 超效率 matlab程序(Solve the DEACCR BCC super efficiency matlab program)
- 2019-02-20 10:25:28下载
- 积分:1
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(+)chengxiang
说明: 声全息技术,里边包括全息技术的matlab程序,数据等。(Sound holographic technology, including holographic technology matlab procedures, data, etc.)
- 2019-05-30 10:04:40下载
- 积分:1
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Fuzzy controller of DC Motor
说明: 压缩包为模糊PID控制的直流电机的速度控制系统仿真,可进行相关学习(The simulation of the speed control system of DC motor with the compression package of fuzzy PID control can be used for relevant learning)
- 2020-03-22 12:07:51下载
- 积分:1
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jlsins
一段关于捷联惯导系统姿态解算的Matlab仿真程序,有关于误差的计算(Matlab simulation program solver paragraph on the attitude of SINS)
- 2012-06-08 12:20:30下载
- 积分:1
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Matlab-for-finite-time-program
利用matlab进行时域有限差分模拟电磁场分布的编程案例。(Matlab FDTD programming for simulation of electromagnetic field distribution.)
- 2014-12-19 21:32:43下载
- 积分:1
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Leastsquaresfitting
采用最小二乘逼近作为拟合实验数据的方法,利用F检验,确定实验数据拟合优度及最佳阶数,用编制的程序来拟合实验数据,得到了较好的结果(Least-squares fitting)
- 2009-12-08 10:59:52下载
- 积分:1
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shuxuejianmo_3
说明: 某厂向用户提供发动机,合同规定,第一、二、三季度末分别交货40台、60台、80台.每季度的生产费用为 (元),其中x是该季生产的台数.若交货后有剩余,可用于下季度交货,但需支付存储费,每台每季度c元.已知工厂每季度最大生产能力为100台,第一季度开始时无存货,设a=50、b=0.2、c=4,问工厂应如何安排生产计划,才能既满足合同又使总费用最低.讨论a、b、c变化对计划的影响,并作出合理的解释(To provide users with a factory engine, contract, first, second and third quarter respectively, delivered at the end of 40, 60, 80. Quarterly cost of production (million), in which x is the quarter of the number of production. If the remaining after delivery, can be used for delivery next quarter, subject to payment of storage fees, for each element c of each quarter. The largest known plant production capacity of each quarter to 100, the beginning of the first quarter of stock, set up a = 50, b = 0.2, c = 4, asked how to arrange the production of the factory plans to meet the total cost of the contract makes the minimum . Discussion of a, b, c of the impact of change on the plan and make a reasonable explanation)
- 2009-07-24 22:58:49下载
- 积分:1