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CompDam_DGD
摩擦力是抵抗固體表面,流體層和材料元件相對滑動的相對運動的力。有幾種類型的摩擦:幹摩擦是一種與之相反的力(friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the)
- 2020-06-23 10:00:01下载
- 积分:1
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multiplication-table
只是一个课堂上做的九九乘法表,可能很多人做过(Just a class to do multiplication table, many people may have done)
- 2011-10-21 19:43:24下载
- 积分:1
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AR(5)
利用AR模型进行时间序列预测的程序源代码,使用最小二乘估计法进行参数估计。拟合效果非常好。(use AR model for time series prediction of the source code, the use of least squares estimation method to estimate parameters. Fitting very good results.)
- 2020-12-29 15:19:01下载
- 积分:1
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PCAmodel
用基于主元分析的方法对被控过程进行建模,可以消除变量之间的贡献性。(Accused of process modeling method based on principal component analysis, contribution between the variables can be eliminated.)
- 2012-09-26 17:33:39下载
- 积分:1
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Soct
假设有一个能装入总体积为T的背包和n件体积分别为w1 , w2 , … , wn 的物品,能否从n件物品中挑选若干件恰好装满背包,即使w1 +w2 + … + wn=T,要求找出所有满足上述条件的解。例如:当T=10,各件物品的体积{1,8,4,3,5,2}时,可找到下列4组解:(1,4,3,2),(1,4,5),(8,2),(3,5,2)。
[需求分析](Suppose there are a load of the backpack of the total volume of T and n volumes were w1, w2, ... wn items, whether selected from n items a number of exactly filled backpack, even if w1+w2+ ...+ wn = T, find out the solution of all the above conditions are met. For example: when T = 10, the volume of items {1,8,4,3,5,2}, can be found in the following four solutions: (1,4,3,2), (1,4,5 ), (8,2), (3,5,2). [Needs Analysis])
- 2012-06-14 16:25:10下载
- 积分:1
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Rongekutta
四阶龙格库塔法函数更新四元数程序代码,采用VC编写(Fourth-order Runge-Kutta method function is updated quaternion code)
- 2010-03-03 21:53:15下载
- 积分:1
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Gaussianeliminationmethod
用C语言来求解n维线性方程组的解,即高斯消元法求解线性方程组(Gaussian elimination method with n-dimensional linear equations)
- 2010-07-14 21:27:06下载
- 积分:1
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xconv2
频域二维卷积算法,通过在频域用fft计算,加速了卷积的实现过程(Frequency domain of two-dimensional convolution algorithm, by calculating the frequency domain using fft and accelerate the realization of the convolution process)
- 2020-11-20 19:59:37下载
- 积分:1
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连续体和结构的非线性有限元
说明: finite element theory
- 2020-03-29 10:47:02下载
- 积分:1
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counting-the-student-number
统计[0, 100] 之间的学生人数并且求出最值和均值(Statistics [100], the number of students and find the best value and the mean)
- 2012-06-24 21:37:37下载
- 积分:1