The-Modulated-Wideband-Converter-

model non linear of 10 bit Pipelined ADC

说明：  囚犯问题，100个囚犯如何获得释放的matlab仿真程序源代码(Prisoners, 100 prisoners were released on how the matlab simulation program source code)

it defines about apche ant simulations

通过均值聚类实现四类数据的分类，一直在用(means clustering )

说明：  交织分复用多址(IDMA)的matlab程序。IDMA可以通过简单的迭代运算分离各用户的信号，是一种有前途的技术。(matlab program for Interleaver division multiple accessing(IDMA).)

在Matlab的Simulink仿真环境，模拟光伏电池板电流输入控制电压输出(In Matlab Simulink simulation environment, the simulation of photovoltaic panels current input control voltage output)

本仿真为电动汽车充电桩设计，采用了隔离式的DC/DC环节(Simulation to charge electric cars pile design, isolated DC/DC link)

Plane Stress with body and point loads, T3 triangle XY COORDINATES CLOSED FORM INTEGRALS Change E_e to get Plane Strain

Neural Predictive Control using Quasi Newton Optimization

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)