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IRIS
Source code for Iris recognition on Matlab
- 2011-05-12 14:43:33下载
- 积分:1
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LAN2
LMS算法和NLMS算法的比较。模拟的是回声消除。但没办法消除回声,只能做有限的处理。(LMS algorithm and NLMS algorithms. Simulate the echo cancellation. But no way to eliminate echo, can do only limited processing.)
- 2010-06-03 18:01:30下载
- 积分:1
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_protk_install_example
ProTK installation example
- 2014-09-29 05:38:41下载
- 积分:1
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MUSIC-based-decorrelation-
关于基于解相干的MUSIC的源程序,分别列出Toeplitz,矩阵分解,奇异值分解等情况~~~(ABOUT MUSIC based decorrelation of the source, respectively, which are listed several possible scenarios ~ ~ ~)
- 2020-09-16 11:27:56下载
- 积分:1
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3bit-spatial-modulation
当空间调制(sm)系统中每个符号含有3bits信息(即3bit/s/Hz的频谱利用率)时我们选择:4根发送天线,BPSK调制方式和2根发送天线,4QAM调制方式进行比较。(When the spatial modulation (sm) system, each symbol comprising 3bits information (i.e. 3bit/s/Hz spectral efficiency) when we choose: four transmitting antennas, BPSK modulation method and two transmission antennas, 4QAM modulation for comparison.)
- 2013-08-27 17:51:35下载
- 积分:1
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ImageRetrieval-master-(2)
image retrieval,content based image retrieval
- 2013-12-05 19:25:49下载
- 积分:1
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bisection
This program solves the following equation using bi-section method.
- 2012-02-15 16:51:45下载
- 积分:1
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Foreground-detection-procedures
前景检测程序,MATLAB实现,有背景差分,帧差法,混合高斯模型,光流法。(Foreground detection procedures, MATLAB, background difference, frame difference method, the gaussian mixture model and optical flow method.)
- 2016-06-02 22:25:03下载
- 积分:1
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hoteltransform
hotelling transformation has been written with help of Matlab 2007a. This technology has been applied to transform images. A test image has been included in the file for explanation.
It accpets 256 color map bmp image as input and produces the output.
- 2010-06-30 17:06:09下载
- 积分:1
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pca
说明: 在MATLAB上所使用的PCA程序,主要應用於過濾相對較不重要的特徵值(dimension),例如在三度空間的某些點具有(x,y,z)值,因為這些點有共同的一個持徵,就是z值相對於x,y值來得小很多(不明顯),所以就以X,Y軸來表示這些點。此時就達成去除掉z的特徵值(dimension)。
(MATLAB used in the PCA procedure, mainly used in filtering relatively unimportant eigenvalue (dimension), for example, in some points with three-dimensional (x, y, z) values, because these points have a common one sign holders, that is, z values compared with the x, y values much smaller than (not obvious), so on to X, Y axis to express these points. Reached at this time to get rid of z eigenvalues (dimension).)
- 2008-09-27 14:10:06下载
- 积分:1