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23_52
用MATLAB语言编制定的用于流体计算和传热的程序(Compiled with the MATLAB language for set procedures for fluid and heat transfer calculations)
- 2010-06-20 23:48:35下载
- 积分:1
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chap5_3s
智能控制的应用1 基于模糊控制的控制器仿真
简单易懂 功能强大(intelligent control based on the application of a fuzzy controller to control the simulation is simple to understand the powerful)
- 2007-05-31 17:20:34下载
- 积分:1
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pic16f676
i need same sours code pls help pudn
- 2012-09-04 20:21:03下载
- 积分:1
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Machine-learning
多帧图像超分辨率重建,通过机器学习来实现,效果不错。(Multi-frame image super-resolution reconstruction, through machine learning to achieve good results.)
- 2013-11-11 19:11:59下载
- 积分:1
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频率调制的Matlab演示程序-fm.m
%fm.m %频率调制的Matlab演示程序. %被调信号为m(t)=sin(100t).( fm.m frequency modulation of Matlab demo program. transferred signal m (t) = sin (100t).)
- 2005-03-26 20:48:24下载
- 积分:1
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TrNum
计算一维光子晶体透射率的程序,
可以手动输入任意序列,
程序只针对两种介质组成的序列.(One-dimensional photonic crystal transmission process, you can manually enter any sequence, the program only for sequences composed of two media.)
- 2010-10-30 10:06:28下载
- 积分:1
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GA_implementation
MATLAB has a wide variety of functions useful to the genetic algorithm practitioner
and those wishing to experiment with the genetic algorithm for the first time.
Given the versatility of MATLAB’s high-level language, problems can be coded
in m-files in a fraction of the time that it would take to create C or Fortran programs
for the same purpose. Couple this with MATLAB’s advanced data analysis,
visualisation tools and special purpose application domain toolboxes and the user is
presented with a uniform environmentwith which to explore the potential of genetic
algorithms.
- 2010-11-25 18:18:34下载
- 积分:1
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BPSelf
该算法利用BP神经网络描述了一个同心圆的分类算法。特点是可以任意定义多个隐层及隐层内的神经元数目。(the algorithm discribed a category of samecircle.with it you can define any number of buried layer and never cell number of each buried layer.)
- 2012-04-02 20:04:04下载
- 积分:1
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gatbx
Sheffield工具箱的简单例子,有作者修改,其中doc文件为介绍(the example of Sheffield GA)
- 2013-05-08 10:54:03下载
- 积分:1
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public
Base64编码说明 Base64编码要求把3个8位字节(3*8=24)转化为4个6位的字节(4*6=24),之后在6位的前面补两个0,形成8位一个字节的形式。 如果剩下的字符不...(Base64-encoded instructions require the Base64 encoding three 8-bit bytes (3* 8 = 24) was converted to 4 6 bytes (4* 6 = 24), then in front of the two s complement 6 0, 8 is formed bits in a byte form. If the rest of the characters do not ...)
- 2015-03-18 17:44:08下载
- 积分:1