SimpleTetrisGame

C++五子棋代码，有详细的算法注释，代AI算法...可直接运行(C++ gobang game code-with AI。it can work directly)

人机下棋：在3×3棋盘上，计算机为一方，用户为一方，交替画“X”和“O”，在行、列、对角线上谁先练成一条直线谁就获得胜利。用类的思想完成，具体功能要求如下： （1）状态显示：计算机可正确显示棋盘，给出提示信息和胜负判断。 （2）用户选择：用户可以选择是先下还是后下，并选择棋子是“X”还是“O”。 （3）每一步都用图形化方式顺序输出 (Man-machine chess: on the 3 X 3 board, the computer for one party, the user for a party, draw an X and O alternately, in the row, column and diagonal who practice who would win in a straight line. Finish, with the ideas of the class specific functional requirements are as follows: (1) status display: the computer can correctly display board, giving prompt information and the outcome of judgment. (2) the user choice: the user can next is first or after, and the pieces is a X or O .)

一个用Visal C++编写的俄罗斯方块小程序。(A used Visal C++ Prepared Tetris applet.)

射击游戏，吃豆子的游戏，简单的界面，逻辑很流畅(Shooting game, Pacman game, simple interface, logic is smooth)

该工程是一个非常完整的,优化的五子棋源代码(VC),可以帮你学习路径选择算法和vc编程.(The project is a very complete, optimized Gobang source code (VC), can help you learn the path selection algorithm and programming vc.)

五子棋是有两个人在一盘棋上进行对抗的竞技运动。在对局开始时，先由用户选择哪方先开局，先开局一方将一枚棋子落在一点上，然后由另一方在对方棋周围的交叉点上落子，如此轮流落子，直到某一方首先在棋盘的直线、横线或斜线上形成连续的五子则该方就算获胜。此时，算法结束。当有任何一方想退出时，都可在算法中实现。(Backgammon is a competitive sport confrontation of two people in a game of chess. At the beginning of the game, the first users to choose which side first start, first start the party will be a pawn falls point, and then by the other party on the other chess around the intersection of Lazi, so turns Lazi, until the party first the chessboard straight, horizontal or diagonal to form a continuous five sons even if the party wins. In this case, the algorithm ends. When either party wishes to withdraw from, can be realized in the algorithm.)

说明：  中国象棋棋盘C#实现，主要用于学习面向对象相关知识(Chinese chess board C# to achieve, mainly for learning object-oriented knowledge)

网狐原版网站后台，绝对完整！超值！！！！(code wh web aaaaaaa)

俄罗斯方块 Visual C++ 6 源码(Tetris Visual C++ 6 source)

一个自己写的五子棋程序。包括人机和双人对战。(Renju program. Including the man-machine and two against.)